微调开关外壳问题 [英] Spinner Switch Case Problem

问题描述

编辑：我已经添加了我所有的code（不包括包装，进口......），如果我尝试它崩溃运行......任何想法，为什么

？

 公共类BaseConverter延伸活动{
/ **第一次创建活动时调用。 * /
INT inputBase;
INT outputBase;

@覆盖
公共无效的onCreate（包savedInstanceState）{
    super.onCreate（savedInstanceState）;
    的setContentView（R.layout.main）;

    微调input_spinner =（微调）findViewById（R.id.InputSpinner）;
    微调output_spinner =（微调）findViewById（R.id.OutputSpinner）;

    ArrayAdapter＆LT; CharSequence的＆GT;适配器= ArrayAdapter.createFromResource（
            对此，R.array.base_numbers_array，android.R.layout.simple_spinner_item）;
    adapter.setDropDownViewResource（android.R.layout.simple_spinner_dropdown_item）;
    input_spinner.setAdapter（适配器）;
    output_spinner.setAdapter（适配器）;

    input_spinner.setOnItemSelectedListener（新InputItemSelectedListener（））;

    output_spinner.setOnItemSelectedListener（新OutputItemSelectedListener（））;
}

公共类InputItemSelectedListener实现OnItemSelectedListener {

    公共无效onItemSelected（适配器视图＆LT;＆GT;父，
        视图中查看，INT POS，长I​​D）
        {
        / *开关（的Integer.parseInt（parent.getItemAtPosition（POS）的ToString（））
            案（（整数）parent.getItemAtPosition（POS））的intValue（）。
                inputBase = 2;
                打破;
            案例8：
                inputBase = 8;
                打破;
            案例10;
                inputBase = 10;
                打破;
            案例16;
                inputBase = 16;
                打破;
                * /

        Toast.makeText（parent.getContext（），你选择的输入基地+
                parent.getItemAtPosition（POS）的ToString（），Toast.LENGTH_SHORT）.show（）;
        }

    公共无效onNothingSelected（适配器视图父）
    {
      // 没做什么。
    }
}

公共类OutputItemSelectedListener实现OnItemSelectedListener {

    公共无效onItemSelected（适配器视图＆LT;＆GT;父，
        视图中查看，INT POS，长I​​D）{
      Toast.makeText（parent.getContext（），你所选的输出基地+
          parent.getItemAtPosition（POS）的ToString（），Toast.LENGTH_SHORT）.show（）;
    }

    公共无效onNothingSelected（适配器视图父）{
      // 没做什么。
    }
}
 

}

，现在需要有一个开关 - 这一切围绕着什么样的价值，他们选择了它的情况。它们都是数字（的选择），并存储在一个整数数组。我如何设置一个开关的情况下是否正确？我试图做一个简单的事情，像

 情况下（（的Integer.parseInt（parent.getItemAtPosition（POS）的ToString（））
 

解决方案

所以，我理解了它。你需要做的阵列的字符串数组及使用：     ArrayAdapter适配器=新的ArrayAdapter

等.....

然后用

 的Integer.parseInt（parent.getItemAtPosition（位置）的ToString（））;
 

要找到任何你选择的数值。注意：它必须是所有的数值或者它会给你一个错误

EDIT: i have added in all of my code (excluding package and imports.....) and if i try to run it it crashes...... any ideas why?

public class BaseConverter extends Activity {
/** Called when the activity is first created. */
int inputBase;
int outputBase;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Spinner input_spinner = (Spinner) findViewById(R.id.InputSpinner);
    Spinner output_spinner = (Spinner) findViewById(R.id.OutputSpinner);

    ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(
            this, R.array.base_numbers_array, android.R.layout.simple_spinner_item);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    input_spinner.setAdapter(adapter);
    output_spinner.setAdapter(adapter);

    input_spinner.setOnItemSelectedListener(new InputItemSelectedListener());

    output_spinner.setOnItemSelectedListener(new OutputItemSelectedListener());
}

public class InputItemSelectedListener implements OnItemSelectedListener {

    public void onItemSelected(AdapterView<?> parent,
        View view, int pos, long id)
        {
        /*  switch (Integer.parseInt(parent.getItemAtPosition(pos).toString())
            case ((Integer)parent.getItemAtPosition(pos)).intValue(); 
                inputBase = 2;
                break;
            case 8:
                inputBase = 8;
                break;
            case 10;
                inputBase = 10;
                break;
            case 16;
                inputBase = 16;
                break;
                */

        Toast.makeText(parent.getContext(), "You selected input base " +
                parent.getItemAtPosition(pos).toString(), Toast.LENGTH_SHORT).show();
        }

    public void onNothingSelected(AdapterView parent) 
    {
      // Do nothing.
    }
}

public class OutputItemSelectedListener implements OnItemSelectedListener {

    public void onItemSelected(AdapterView<?> parent,
        View view, int pos, long id) { 
      Toast.makeText(parent.getContext(), "You selected output base " +
          parent.getItemAtPosition(pos).toString(), Toast.LENGTH_SHORT).show();
    }

    public void onNothingSelected(AdapterView parent) {
      // Do nothing.
    }
} 

}

and now need to have a switch - case scenario that all revolves around what the value they selected it. they are all numbers (the choices) and are stored in an Integer array. How do i set up that switch-case correctly? i tried doing a simple thing like

 case ((Integer.parseInt(parent.getItemAtPosition(pos).toString())

解决方案

So i figured it out. you need to make the array a STRING array and the use: ArrayAdapter adapter = new ArrayAdapter

etc.....

then use

Integer.parseInt(parent.getItemAtPosition(position).toString());

to find the numerical value of whatever you selected. NOTE: it must be all numerical or it will give you an error.

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