'替换'来自< algorithm>运作不正常 [英] 'Replace' from <algorithm> not functioning correctly

问题描述

出于某种原因，< algorithm> 中的替换模板不希望对我有效。请参阅下面的示例代码：

For some reason, the replace template from <algorithm> does not want to work for me. See example code below:

#include <iostream>
#include <string>
#include <algorithm>
using namespace std;

int main() {
	string s = "Hello, world!";
	replace(s.begin(), s.end(), "l", "i");
	cout << s << endl;
	return 0;
}

代码没有语法错误，但编译器仍然给我带来以下错误：

There are no syntax errors with the code, but the compiler is still throwing me the following errors:

In file included from /usr/include/c++/4.9/algorithm:62:0,
                 from prog.cpp:3:
/usr/include/c++/4.9/bits/stl_algo.h: In instantiation of 'void std::replace(_FIter, _FIter, const _Tp&, const _Tp&) [with _FIter = __gnu_cxx::__normal_iterator<char*, std::basic_string<char> >; _Tp = char [2]]':
prog.cpp:8:38:   required from here
/usr/include/c++/4.9/bits/stl_algo.h:4234:15: error: ISO C++ forbids comparison between pointer and integer [-fpermissive]
  if (*__first == __old_value)
               ^
/usr/include/c++/4.9/bits/stl_algo.h:4235:13: error: invalid conversion from 'const char*' to 'char' [-fpermissive]
    *__first = __new_value;
             ^

谢谢，全部！



我尝试了什么：



我尝试了多个版本，但似乎没有任何效果。谷歌只给了我模板，我已经知道了。

Thanks, all!

What I have tried:

I have tried multiple versions of this, but nothing seems to work. Google just gives me the template, which I already know.

推荐答案

你的调用替换（迭代器，迭代器，const char *，const char * ）与 std :: replace 模板不匹配：

Your call replace(iterator, iterator, const char*, const char *) does not match the std::replace template:

template<typename _FIter, typename _Tp>
  void
  replace(_FIter, _FIter, const _Tp&, const _Tp&);

_Tp 是 char 这里因为 std :: string 迭代器指向 char 。



所以你必须使用

_Tp is char here because the std::string iterators are pointing to char.

So you must use

replace(s.begin(), s.end(), 'l', 'i');

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