如何用另外多个单词搜索和替换多个单词？并且引号之间没有变化？ [英] How to search and replace multiple words with onother multiple words ? and without change between quoted marks ?

问题描述

我想更改此字符串..



str =dw（'download'）;



到这个字符串..



document.write（'download'）;



不知怎的，它的回报..

d.write（'dowritenload'）;



这里我不想改变''或'之间的字母标记并返回d作为文档。



i试图在w3schools找到它。有每个代码的样本，但我不知道如何在我的脚本中相互安排这些代码？



我尝试过： < br $> b $ b

i want to change this string..

str = "d.w('download');"

to this string..

document.write('download');

somehow its returns..
d.write('dowritenload');

here i dont want to change letters between '' or "" marks and returns d as document.

i tried to find it on w3schools. there are every code's sample but i dont know how to arrange those code with each other in my script ?

What I have tried:

推荐答案

str = "d.w('download');"

re = str.replace(/d/g, "document");
re = str.replace(/w/g, "write");

您可能希望将您的替换限制为'd'和'w'的第一个发生率。检查你的正则表达式语法并从那里弄清楚。







例如，回到你的w3Schools参考： RegExp g Modifier [ ^ ]

试试

try

str = "d.w('download');"
str = str.replace('d.w', "document.write");

// or
str = str.replace('d.', "document.");
str = str.replace('w(', "write(");

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