使用界面中的AsyncTask onPostExecute Android的返回值 [英] Android return value in AsyncTask onPostExecute using Interface

问题描述

在此跌破codeI想回到从的AsyncTask 值与使用接口。但我得到一个错误的值，我无法从 onPostExecute 返回正确的值。

in this below code i want to return value from AsyncTask with using an Interface. but i get wrong value and i can not return correct value from onPostExecute.

我正在开发的这个<一href="http://stackoverflow.com/questions/12575068/how-to-get-the-result-of-onpostexecute-to-main-activity-because-asynctask-is-a">link教程我的code。我可以正确与不使用。

i'm developed this link tutorials with my code. i can not use correctly with that.

接口：

public interface AsyncResponse {
    void processFinish(String output);
}

KSOAP 主类：

public class WSDLHelper  implements AsyncResponse{
    public SoapObject request;

    private String Mainresult;

    public String call(SoapObject rq){

        ProcessTask p =new ProcessTask(rq);
        String tmp = String.valueOf(p.execute());

        p.delegate = this;

        return Mainresult;
    }


    @Override
    public void processFinish(String output) {

        this.Mainresult = output;
    }
}
class ProcessTask extends AsyncTask<Void, Void, Void > {
    public AsyncResponse delegate=null;

    SoapObject req1;
    private String result;
    public ProcessTask(SoapObject rq) {
        req1 = rq;
    }

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
    }

    @Override
    protected Void doInBackground(Void... params) {

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.setOutputSoapObject(this.req1);

        AndroidHttpTransport transport = new AndroidHttpTransport(Strings.URL_TSMS);
        transport.debug = true;

        try {
            transport.call(Strings.URL_TSMS + this.req1.getName(), envelope);
            this.result = envelope.getResponse().toString();
        } catch (IOException ex) {
            Log.e("" , ex.getMessage());
        } catch (XmlPullParserException ex) {
            Log.e("" , ex.getMessage());
        }

        if (result.equals(String.valueOf(Integers.CODE_USER_PASS_FALSE))) {
            try {
                throw new TException(PublicErrorList.USERNAME_PASSWORD_ERROR);
            } catch (TException e) {
                e.printStackTrace();
            }

        }

        Log.e("------------++++++++++++++++-----------", this.result);

        return null;
    }

    protected void onPostExecute(String result) {
    /* super.onPostExecute(result);*/
        delegate.processFinish(this.result);
    }

}

请帮我解决这个问题。

推荐答案

这是行不通的。您正在创建并执行AsyncTask的（异步！），然后调用返回Mainresult（同步！），当它没有收到效果呢。解决的办法是为删除多余的类WSDLHelper和访问ProcessTask直接

That can't work. You are creating and executing the AsyncTask (asynchronously!) and then call return Mainresult (synchronously!) when it hasn't received the result yet. The solution is to remove the redundant class WSDLHelper and access ProcessTask directly

旁边的是，你使用的AsyncTask错误（节能将它作为一个参数的结果，在一个类变量，而不是）。下面是完整版本：

Beside that, you're using AsyncTask incorrectly (saving the result in a class variable instead of passing it as a parameter). Here's the full version:

public class ProcessTask extends AsyncTask<Void, Void, String> {
public AsyncResponse delegate=null;

SoapObject req1;

public ProcessTask(SoapObject rq, AsyncResponse delegate) {
    req1 = rq;
    this.delegate = delegate;
}

@Override
protected void onPreExecute() {
    super.onPreExecute();
}

@Override
protected Void doInBackground(Void... params) {

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.setOutputSoapObject(this.req1);

    AndroidHttpTransport transport = new AndroidHttpTransport(Strings.URL_TSMS);
    transport.debug = true;

    String result = null;
    try {
        transport.call(Strings.URL_TSMS + this.req1.getName(), envelope);
        result = envelope.getResponse().toString();
    } catch (IOException ex) {
        Log.e("" , ex.getMessage());
    } catch (XmlPullParserException ex) {
        Log.e("" , ex.getMessage());
    }

    if (result != null && result.equals(String.valueOf(Integers.CODE_USER_PASS_FALSE))) {
        try {
            throw new TException(PublicErrorList.USERNAME_PASSWORD_ERROR);
        } catch (TException e) {
            e.printStackTrace();
        }

    }

    Log.e("------------++++++++++++++++-----------", result);

    return result;
}

protected void onPostExecute(String result) {
/* super.onPostExecute(result);*/
    delegate.processFinish(result);
}

}

现在你可以执行ProcessTask从外面这样，这将确保您接收结果异步

Now you would execute ProcessTask from outside like this, which will make sure you receive the result asynchronously:

new ProcessTask(rq, new AsyncResponse() {
    @Override
    public void processFinish(String output) {
        // do whatever you want with the result
    }
}).execute();

这篇关于使用界面中的AsyncTask onPostExecute Android的返回值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！