我想做最简单的计算器。 [英] I am trying to do the simplest calculator.

问题描述

我想从我的两个盒子中获取输入并将其显示在我的标签上，当达到效果时会弹出。



这里是代码我单击+按钮时使用

I want to get the input from my two boxes and display it on my label,which pops up when a result is achieved.

here is the code I use when a "+" button is clicked

double numberOne = double.Parse(number1.Text);
double numberTwo = double.Parse(number2.Text);
result = numberOne+numberTwo;
answerLabel.Text =  result.ToString();

这是否有用，我可以在其他运营商上使用



我尝试了什么：



我尝试在每次操作时使用true和false并使用如果声明，但我只是想尝试更好更有效的东西



注意：我知道已经有一个解决方案和很多它们，我只是在尝试努力解决我的解决问题的能力，这就是我现在想出来的。

Is this going to ever work and can I use it on the other operators

What I have tried:

I tried using true and false on each operation and doing it with an if statement but I just want to try something better and more efficient

Note: I know there is already a solutions and a lot of them as well, I am just trying to work on my problem solving skills and that is what I came up with for now.

推荐答案

是的，它会起作用。

但是......我建议用而不是double.Parse你使用TryParse：

Yes, it'll work.
But...I'd suggest that instead of double.Parse you use TryParse:

double numberOne;
if (!double.TryParse(number1.Text, out numberOne))
   {
   MessageBox.Show(number1.Text + " is not a number!", "Error", MessageBoxButtons.OK);
   number1.Focus();
   return;
   }
double numberTwo;
if (!double.TryParse(number2.Text, out numberTwo))
   {
   MessageBox.Show(number2.Text + " is not a number!", "Error", MessageBoxButtons.OK);
   number2.Focus();
   return;
   }
double result = numberOne + numberTwo;
answerLabel.Text =  result.ToString();

这样，当用户犯错时，你的程序不会崩溃。

That way, when the user makes a mistake, your program doesn't just crash.

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