如何在列表视图中获取字母条目？ [英] How to get alphabetic entries in the listview ?
问题描述
我尝试按升序修改查询，但输出仍不按字母顺序排列。
以下是 MainActivity.java文件：
包com.example.user.phonebook;
import android.app.ListActivity;
import android.content.ContentResolver;
import android.content.Context;
import android.content.CursorLoader;
import android.database .cursor;
导入android.net.Uri;
导入android.os.Build;
导入android.os.Bundle;
导入android.provider.ContactsContract;
导入android.util.Log;
导入android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget .TextView;
import java.util.ArrayList;
import java.util.Collections;
公共类MainActivity扩展ListActivity {
ArrayList< contact>联系方式;
@Override
protected void onCreate（Bundle savedInstanceState）{
super.onCreate（savedInstanceState） ;
setContentView（R.layout.activity_main）;
contacts = new ArrayList< contact>（）;
Uri allContacts = ContactsContract.Contacts.CONTENT_URI;
//声明我们的光标
光标c ;
String [] projection = new String []
{ContactsContract.Contacts._ID，
ContactsContract .Contacts.DISPLAY_NAME，
ContactsContract.Contacts.HAS_PHONE_NUMBER};
if（Build.VERSION。 SDK_INT< 11）{
// ---如果设备ID在Honey之前在OS上运行梳子
//使用Activity类的managedQuery（）来检索托管游标
c = managedQuery（allContacts，projection，null，null，null）;
} else {
// --- Honeycomb后来使用游标加载器类来检索托管游标---
CursorLoader cursorLoader = new CursorLoader（
this，
allContacts，
projection，
null，
null，
null）;
c = cursorLoader.loadInBackground（）;
}
PrintContacts（c）;
MyClassAdapter适配器;
//再次检测android版本..
if（Build.VERSION.SDK_INT< 11）{
// ---如果它在Honeycomb之前---
adapter = new MyClassAdapter（
this，R.layout.row_line，contacts）;
} else {
// --- Honeycomb及以后---
adapter = new MyClassAdapter（
this，R.layout.row_line，contacts）;
}
this.setListAdapter（适配器）;
}
private void PrintContacts（光标c）{
ContentResolver cr = getContentResolver（）;
// ---显示联系人ID和姓名电话号码----
if（c.moveToFirst（））{
do {
// ---获取联系人ID和名称
字符串contactID = c.getString（c.getColumnIndex（
ContactsContract.Contacts._ID））;
String contactDisplayName =
c.getString（c。 getColumnIndex（
ContactsContract.Contacts.DISPLAY_NAME））;
Log.v（Content Providers，contactID +，+
contactDisplayName ）;
String contactDisplayPhone =;
// ---获取电话号码---
int hasPhone =
c.getInt（c.getColumnIndex（
ContactsContract.Contacts.HAS_PHONE_NUMBER））;
if（hasPhone == 1 ）{
光标phoneCursor =
getContentResolver（）。query（
ContactsContract.CommonDataKinds.Phone.CONTENT_URI，null，null
，null，ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME +ASC）;
while（phoneCursor.moveToNext（） ）{
Log.v（内容提供商，
contactDisplayPhone = phoneCursor.getString（
phoneCursor.getColumnIndex（
ContactsContract.CommonDataKinds.Phone.NUMBER）））;
}
phoneCursor.close（）;
}
contacts.add（新联系人（contactDisplayName，contactDisplayPhone））;
} while（c.moveToNext（）） ;
}
}
公共课程联系{
public String contactName =;
public String contactNumber =;
public Contact（String name，String number）{< br $> b $ b
contactName = name;
contactNumber = number;
}
}
公共类MyClassAdapter扩展ArrayAdapter< contact> {
私人类ViewHolder {
私有TextView名称;
私有TextView号码;
}
public MyClassAdapter（Context context，int textViewResourceId，ArrayList< contact> items）{
super（context，textViewResourceId，项目）;
}
公共视图getView（int position，View convertView，ViewGroup parent）{
ViewHolder viewHolder;
if（convertView == null）{
convertView = LayoutInflater.from（this.getContext（））
.inflate（ R.layout.row_line，parent，false）;
viewHolder = new ViewHolder（）;
viewHolder.name =（TextView）convertView .findViewById（R.id.contactName）;
viewHolder.number =（TextView）convertView.findViewById（R.id.contactNumber）;
convertView.setTag（viewHolder）;
}其他{
viewHolder =（ViewHolder）convertView.getTag（）;
}
联系item = getItem（position）;
if（item！= null）{
viewHolder.name.setText（item.contactName）;
viewHolder.number.setText（item.contactNumber）;
}
返回convertView;
}
}
}
我尝试了什么：
i尝试使用SimpleCursorAdapter，但条目中有字母但电话号码不可见。你可以参考这个链接：http：//stackoverflow.com/questions/38618185/how-should-i-solve-the-issue-of-duplicate-contact-names-and-phone-numbers-not-vi
I tried modifying the query in ascending order but still the output is not in alphabetical order.
The following is the MainActivity.java file:
package com.example.user.phonebook;
import android.app.ListActivity;
import android.content.ContentResolver;
import android.content.Context;
import android.content.CursorLoader;
import android.database.Cursor;
import android.net.Uri;
import android.os.Build;
import android.os.Bundle;
import android.provider.ContactsContract;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.TextView;
import java.util.ArrayList;
import java.util.Collections;
public class MainActivity extends ListActivity {
ArrayList<contact> contacts;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
contacts = new ArrayList<contact>();
Uri allContacts = ContactsContract.Contacts.CONTENT_URI;
//declare our cursor
Cursor c;
String[] projection = new String[]
{ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.Contacts.HAS_PHONE_NUMBER};
if (Build.VERSION.SDK_INT < 11) {
//---if the device ids running on OS before Honeycomb
//use the managedQuery() of the Activity class to retrieve a managed cursor
c = managedQuery(allContacts, projection, null, null, null);
} else {
//---Honeycomb and later use the cursor loader class to retrieve managed cursor---
CursorLoader cursorLoader = new CursorLoader(
this,
allContacts,
projection,
null,
null,
null);
c = cursorLoader.loadInBackground();
}
PrintContacts(c);
MyClassAdapter adapter;
//detect the android version again..
if (Build.VERSION.SDK_INT < 11) {
//---if it is before Honeycomb---
adapter = new MyClassAdapter(
this, R.layout.row_line, contacts);
} else {
//---Honeycomb and later---
adapter = new MyClassAdapter(
this, R.layout.row_line, contacts);
}
this.setListAdapter(adapter);
}
private void PrintContacts(Cursor c) {
ContentResolver cr = getContentResolver();
//---display the contact id and name and phone number----
if (c.moveToFirst()) {
do {
//---get the contact id and name
String contactID = c.getString(c.getColumnIndex(
ContactsContract.Contacts._ID));
String contactDisplayName =
c.getString(c.getColumnIndex(
ContactsContract.Contacts.DISPLAY_NAME));
Log.v("Content Providers", contactID + ", " +
contactDisplayName);
String contactDisplayPhone = "";
//---get phone number---
int hasPhone =
c.getInt(c.getColumnIndex(
ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (hasPhone == 1) {
Cursor phoneCursor =
getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,null
, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC");
while (phoneCursor.moveToNext()) {
Log.v("Content Providers",
contactDisplayPhone = phoneCursor.getString(
phoneCursor.getColumnIndex(
ContactsContract.CommonDataKinds.Phone.NUMBER)));
}
phoneCursor.close();
}
contacts.add(new Contact(contactDisplayName, contactDisplayPhone));
} while (c.moveToNext());
}
}
public class Contact {
public String contactName = "";
public String contactNumber = "";
public Contact(String name, String number) {
contactName = name;
contactNumber = number;
}
}
public class MyClassAdapter extends ArrayAdapter<contact> {
private class ViewHolder {
private TextView name;
private TextView number;
}
public MyClassAdapter(Context context, int textViewResourceId, ArrayList<contact> items) {
super(context, textViewResourceId, items);
}
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder viewHolder;
if (convertView == null) {
convertView = LayoutInflater.from(this.getContext())
.inflate(R.layout.row_line, parent, false);
viewHolder = new ViewHolder();
viewHolder.name = (TextView) convertView.findViewById(R.id.contactName);
viewHolder.number = (TextView) convertView.findViewById(R.id.contactNumber);
convertView.setTag(viewHolder);
} else {
viewHolder = (ViewHolder) convertView.getTag();
}
Contact item = getItem(position);
if (item != null) {
viewHolder.name.setText(item.contactName);
viewHolder.number.setText(item.contactNumber);
}
return convertView;
}
}
}
What I have tried:
i tried SimpleCursorAdapter too though in that entries got alphabetical but phone numbers were not visible. you may refer to this link: http://stackoverflow.com/questions/38618185/how-should-i-solve-the-issue-of-duplicate-contact-names-and-phone-numbers-not-vi
推荐答案
请参阅收集| Android开发者 [ ^ ]对于潜在的收集类型。
See Collection | Android Developers[^] for potential collection types.
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