为什么我不能将数据插入我的数据库？ [英] Why I can't insert data into my database?
问题描述
Hi everyone!, I need your help please. I can't able to insert my data info into my database. I already created database in phpmyadmin.
Please check may codes below:
<------donation form code---------->
<!DOCTYPE html>
<html lang="en">
<head>
<title>Donation Form</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<style>
input[type=submit] {
width: 100%;
background-color: #008000;
color: white;
padding: 14px 20px;
margin: 8px 0;
border: none;
border-radius: 4px;
cursor: pointer;
}
input[type=submit]:hover {
background-color: #45a049;
}
</style>
</head>
<body>
<div class="container">
<div class="btn-group btn-group-justified">
<a href="donationform.php" class="btn btn-success">Donate</a>
<a href="volunteerform.php" class="btn btn-warning">Volunteer</a>
</div>
<br><center><p>Make an online donation to help us, care and support services to the needy. Please submit your donation form below.</p></center>
<div>
<form class="form-horizontal" role="form">
<div class="container">
<h2>DONATION FORM</h2><br>
<form action="insert.php" method="post">
<div class="form-group">
<label class="control-label col-sm-2" for="fname">Donor Full-Name: </label>
<div class="col-sm-10">
<input type="text" name="fname" class="form-control" placeholder="Enter Your Full-Name">
</div>
</div>
<form class="form-horizontal" role="form">
<div class="form-group">
<label class="control-label col-sm-2" for="usedonation">Use my donation for:</label>
<div class="col-sm-10">
<select name="donation for" class="form-control">
<option>Disaster Victims</option>
<option>Local Community</option>
<option>Home visits for medical patients</option>
<option>Environmental (Recyling)</option>
<option>for Events</option>
</select>
</div>
</form>
</div>
<form class="form-horizontal" role="form">
<div class="form-group">
<label class="control-label col-sm-2" for="amount">Donation amount ₱: </label>
<div class="col-sm-10">
<input type="text" name="amount" class="form-control" placeholder="Enter Your Donation Amount">
</div>
</div>
<form class="form-horizontal" role="form">
<div class="form-group">
<label class="control-label col-sm-2" for="card number">Card number: </label>
<div class="col-sm-10">
<input type="text" name="card number" class="form-control" placeholder="Enter Your Card Number ">
</div>
</div>
<form class="form-horizontal" role="form">
<div class="form-group">
<label class="control-label col-sm-2" for="account number:">Account number: </label>
<div class="col-sm-10">
<input type="text" name="account number" class="form-control" placeholder="Enter Your Account Number ">
</div>
</div>
<form class="form-horizontal" role="form">
<div class="form-group">
<label class="control-label col-sm-2" for="preference">Donation Preference: </label>
<div class="col-sm-10">
<select name="preference" class="form-control">
<option>One time donation</option>
<option>Donate every month</option>
<option>Donate every 3 months</option>
<option>Donate every year</option>
</select>
</div>
</form>
</div>
<form class="form-horizontal" role="form">
<div class="form-group">
<label class="control-label col-sm-2" for="email">Email: </label>
<div class="col-sm-10">
<input type="email" name="email" class="form-control" placeholder="Enter Your Email Address">
</div>
</div>
<form class="form-horizontal" role="form">
<div class="form-group">
<label class="control-label col-sm-2" for="c-address">Current Address: </label>
<div class="col-sm-10">
<input type="c-address" name="address" class="form-control" placeholder="Enter Your Current Address">
</div>
</div>
<form class="form-horizontal" role="form">
<div class="form-group">
<label class="control-label col-sm-2" for="contact number">Telephone/Cell number </label>
<div class="col-sm-10">
<input type="contact number" name="number" class="form-control" placeholder="Enter Your Contact Number">
</div>
</div><br>
<div class="container">
<form class="form-horizontal" role="form">
<div class="form-group">
<label for="comment">Note: </label>
<textarea class="form-control" name="comment" rows="5" name="comments" placeholder="Type your message for us" required></textarea>
</div>
</form>
</div><br><br><br><br>
<input type="submit" value="DONATE">
</div>
</div>
</form>
</div>
</div>
</body>
</html>
<------------insert database code----------->
<html>
<body>
<?php
$servername = "localhost";
$username = "root";
$password = "butipayunghanginnagpaparamdam";
$dbname = "donation";
// Create connection
$conn = new mysqli($localhost, $root, $butipayunghanginnagpaparamdam, $donation);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO donation_form (donor fname, donation for, donation amount, card number, account number, preference, email, address, contact number, note)
VALUES
('fname','donation for','amount','card number','account number','preference','email','address','number','comment')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
</body>
</html>
Please help me in my website project thank you so much in advance. :)
What I have tried:
I tried to used mysqli procedural method
$servername = \"localhost\";
$username = \"username\";
$password = \"password\";
$dbname = \"myDB\";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die(\"Connection failed: \" . mysqli_connect_error());
}
// sql to create table
$sql = \"CREATE TABLE MyGuests (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL,
email VARCHAR(50),
reg_date TIMESTAMP
)\";
if (mysqli_query($conn, $sql)) {
echo \"Table MyGuests created successfully\";
} else {
echo \"Error creating table: \" . mysqli_error($conn);
}
mysqli_close($conn);
?>
What I have tried:
I tried to used mysqli procedural method
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
// sql to create table
$sql = "CREATE TABLE MyGuests (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL,
email VARCHAR(50),
reg_date TIMESTAMP
)";
if (mysqli_query($conn, $sql)) {
echo "Table MyGuests created successfully";
} else {
echo "Error creating table: " . mysqli_error($conn);
}
mysqli_close($conn);
?>
推荐答案
servername = \"localhost\";
servername = "localhost";
用户名 = 根;
username = "root";
password = \"butipayunghanginnagpaparamdam\";
password = "butipayunghanginnagpaparamdam";
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