EDITTEXT框中不能正常工作。安卓 [英] editText box not working properly. Android

问题描述

我试图获取值出来的EditText框和一个按钮的点击，我想如果的EditText框内的文字一定值匹配比较。如果是这样，一个新的意图应被调用。如果没有它应该显示一个错误。下面是我在点击按钮后，code ...

I'm trying to get values out of edittext boxes and on the click of a button, I want to compare if the text inside the edittext box matches a certain value. If it does, a new intent should be called. If it doesn't it should show an error. Here is my code after the button is clicked...

     if(v.getId() == R.id.button1){

        id = et1.getText().toString();
        Toast toast = Toast.makeText(this, "Value of id is: " + id, Toast.LENGTH_SHORT);
        toast.show();

        if(id == "abc"){
            Intent i= new Intent(Slogin.this, Sales.class);
            startActivity(i);
        }else{
            Toast toast = Toast.makeText(this, "Wrong id pass",                                                                            Toast.LENGTH_SHORT);
            toast.show();
        }

现在的问题是，即使当我输入ABC（不包括双引号），它仍然显示我的错误错号通。虽然吐司清楚地表明，我已进入ABD和字符串ID现在持有的价值ABC。帮助需要...

Now the problem is that even when I enter "abc" (without the double commas), it still shows me the error "Wrong id pass". While the Toast clearly shows that I have entered abd and the string id now holds the value "abc". Help required...

推荐答案

试试这个。如果 ID 是 INT 使用这样 ID == 5 。但id是字符串你应该使用 id.equals（ABC）

Try this.. if id is int use like this id == 5. but id is String you should use id.equals("abc")

if(id.equals("abc")){           //Correction is here
            Intent i= new Intent(Slogin.this, Sales.class);
            startActivity(i);
        }else{
            Toast toast = Toast.makeText(this, "Wrong id pass",                                                                            Toast.LENGTH_SHORT);
            toast.show();
        }

== 永远只是比较两个引用（非原语，这是） - 即它测试是否两个操作数指的是同一个对象。

== always just compares two references (for non-primitives, that is) - i.e. it tests whether the two operands refer to the same object.

不过，等于方法可以被覆盖 - 因此，两个不同的对象仍然可以等于......

However, the equals method can be overridden - so two distinct objects can still be equal......

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