如何访问@ url.content（"〜/ content /" +" theme1.css"）javascript中的参数 [英] How to access parameter within @url.content("~/content/" + "theme1.css") javascript

问题描述

How to access Parameter within  @Url.Content("~/Content/" + "Theme1.css") javascript 

我尝试过：



功能变更主题（姓名）{



if（Name ==Theme1）{

var thestyle = document.getElementById（style）;

thestyle.href =@ Url.Content（〜/ Content /+Theme1.css）;

}

}





代替主题1（@ url.Content（〜/ Content /+Theme1.css））我想使用Name变量

What I have tried:

function changetheme(Name) {

if (Name == "Theme1") {
var thestyle = document.getElementById("style");
thestyle.href = "@Url.Content("~/Content/" + "Theme1.css")";
}
}


instead on Theme1 in(@Url.Content("~/Content/" + "Theme1.css")) i want to use Name variable

推荐答案

试试这个

try this

<link id="themelink" href="~/Content/YourCurrentTheme.css" rel="stylesheet" />
<script>
    function changetheme(Name) {
        var thestyle = document.getElementById("themelink");
        var styleName = Name + '.css';
        var href = "@Url.Content("~/Content/")" + styleName;
        thestyle.href = href;
    }
</script>

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