使用指针将2D数组传递给函数 [英] Passing 2D array to function using pointer

问题描述

嗨

我在传递2d数组时遇到错误。

它给我以下错误

错误C2664：无法转换参数1从int [3] [4]到int *

我无法弄清楚我在哪里弄错了。这是我的代码

Hi
I am getting and error while passing 2d array to function.
It gives me following error
error C2664: cannot convert parameter 1 from int [3][4] to int*
I am not able to figure out where i am making mistake. Here is my code

#include<iostream>
#include<conio.h>

using namespace std;

class Demo
{
public:
	void TwoDArrPass1(int *arr,int col,int row)
	{
	}

};

void main()
{
	Demo dd;
	int Arr[3][4] =	{	{1,2,3,4},
						{10,20,30,40},
						{100,200,300,400}
					};
	dd.TwoDArrPass1(Arr,3,4);

	_getch();
}

我的尝试：



我试图搜索但没有弄清楚我的错误。

预先感谢您的帮助

What I have tried:

I have tried to search but not getting any clear idea about my mistake.
Thanks in advance for help

推荐答案

这已被多次询问，因此可以通过网络搜索回答。



所以我已经为你做了这件事，而不是重复已经说过的话：

将2D数组传递给C ++函数 - Stack Overflow [ ^ ]

在C ++中将2d数组传递给指针 - C ++论坛 [ ^ ]

指针指针和指针引用 [ ^ ]

如何将二维数组传递给函数（C ++） [ ^ ]

This has been asked multiple times and can be answered therefore by searching the web.

So I have done this for you instead of repeating something said already:
Passing a 2D array to a C++ function - Stack Overflow[^]
Passing 2d array to pointer in C++ - C++ Forum[^]
Pointer to Pointer and Reference to Pointer[^]
How to Pass a Two Dimensional Array to a Function (C++)[^]

演员可以做到这一点，例如

A cast would do the trick, e.g.

 #include<iostream>

 using namespace std;

class Demo
{
public:
  void TwoDArrPass1(int * arr ,int col,int row)
  {
    for ( int c = 0; c<col; ++c)
    {
      for (int r=0; r<row; ++r)
      {
        cout << arr[row*c+r] << " ";
      }
      cout << endl;
    }
  }

};

int main()
{
  Demo dd;
  int Arr[3][4] = { {1,2,3,4},
            {10,20,30,40},
            {100,200,300,400}
          };
  dd.TwoDArrPass1(reinterpret_cast<int *>(Arr),3,4);
}

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