如何在C＃中编写代码 [英] How do code this in C#

问题描述

大家好，



我有一个必须满足以下三个条件的要求



1一个或多个2 ----只保留一个2，放下休息



Ex：2,2,2,2 - > 2

2.一个或多个3 ----只保留一个3，放下休息



Ex：3,3,3， 3 - > 3



3.一个或多个2 +一个或多个3 .....只保留2个，放弃其余



例如：2,2,3,3,3,3 - > 2.



请帮我编写符合上述所有条件的c＃代码。



谢谢。



我尝试了什么：



if（count of 2） ）> 1

保留前2并删除休息

if（count of 3）> 1

保留前3并删除休息



第3个条件？

解决方案

if（count of 2）> 0

保留前2并删除休息

if（count of 3）> 0

保留前3并删除休息

if（2> 0 &&计数3> 0）

保留前2并删除休息

问题没有正确制定，配方不是从一开始就开始的。



这是个主意：如果input是一个数组，您需要了解在初始化后不能从数组中删除任何元素。因此，您必须创建一个全新的数组对象并将其返回。对于每种情况，您可以计算输出数组中需要多少个数组元素，并使用此长度初始化一个新数组。然后将元素从输入数组复制到输出数组，但是，根据具体情况，不是全部。

-SA

Hi all,

I have a required which should satisfy all three conditions below

1. one or more 2 ---- keep only one 2, drop rest

Ex : 2,2,2,2 - > 2
2. one or more 3----keep only one 3, drop rest

Ex: 3,3,3,3 -> 3

3. one or more 2 + one or more 3 .....keep only 2, drop the rest

Ex : 2,2,3,3,3,3 -> 2.

Please help me in writing c # code which satisfies all above conditions.

Thank you.

What I have tried:

if (count of 2) > 1
retain first 2 and delete rest
if(count of 3) > 1
retain first 3 and delete rest

3rd condition?

解决方案

if (count of 2) > 0
retain first 2 and delete rest
if(count of 3) > 0
retain first 3 and delete rest
if (count of 2 > 0 && count of 3 > 0)
retain first 2 and delete rest

The question is not correctly formulated, the formulation is not started from the beginning.

Here is the idea: if input is an array, you need to understand that you cannot delete any elements from the array after it is initialized. Therefore, you would have to create a brand new array object and return it. For each case, you count how many array elements you need in an output array and initialize a new array with this length. Then you copy elements from the input array to the output array, but, depending on the case, not all of them.

—SA

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