是否可以在本机C ++中使用GDI +方法MakeTransparent [英] Is it possible to use the GDI+ method MakeTransparent in native C++

问题描述

大家好，



我在试图使用GDI +函​​数MakeTransparent时遇到了问题。此函数被列为MSDN中Bitmap的成员，并且在Web上使用.NET提供了大量示例。但是，我在MFC中编写ActiveX控件并使用GDI +，并且报告此方法不可用。错误信息是：



错误C2039：'MakeTransparent'：不是'Gdiplus :: Bitmap'的成员



我从未遇到像这样的GDI +功能。有谁知道发生了什么？



我在XP SP3上使用VS 2010



非常感谢



Tom

Hi all,

I've hit a problem trying to use the GDI+ function MakeTransparent. This function is listed as being a member of Bitmap in MSDN and there are plenty of examples mentioned on the web using it from .NET. However, I'm writing an ActiveX control in MFC and using GDI+ and this method is reported as not being available. The error message is:

error C2039: 'MakeTransparent' : is not a member of 'Gdiplus::Bitmap'

I've never encountered a GDI+ function not being available like this. Does anyone know what's going on?

I'm using VS 2010 on XP SP3

Many Thanks

Tom

推荐答案

这似乎是为了回答你的问题...

将GDI +与MFC或本机C / C ++结合使用 [ ^ ]

This seems written to answer your question ...
Using GDI+ with MFC or native C/C++[^]

这是正确的，请参阅文档 [ ^ ]。

That's correct, see the documentation[^].

谢谢回应。似乎在.NET中公开的Bitmap类与GDI +公开的Bitmap类完全不同。

Thanks for the responses. It seems the Bitmap class exposed in .NET is simply different to that which is exposed by GDI+.

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