Asp.net将多个参数传递给jquery ajax调用 [英] Asp.net pass multiple parameters to jquery ajax call
本文介绍了Asp.net将多个参数传递给jquery ajax调用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script src="jquery-1.12.0.min.js"></script>
<script src="Lash.js"></script>
</head>
<body>
first name <input id="txtFirstname" type="text" /><br />
last name <input id="txtLastname" type="text" /><br />
E-mail <input id="txtEmail" type="text" /><br />
password <input id="txtPassword" type="password" /><br />
<input id="btnRegister" type="button" value="Register" /><br />
</body>
</html>
/// <reference path="jquery-1.12.0.min.js" />
$(document).ready(function () {
$("#btnRegister").click(function () {
Register();
});
function Register() {
var obj = { Firstname: $("#txtFirstname").val(), Lastname: $("#txtLastname").val(), Email: $("#txtEmail").val(), Password: $("#txtPassword").val() };
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "http://localhost:7910/WebService.asmx/Registering",
data:JSON.stringify(obj),
datatype: "json",
success: function (data) {
alert("Successfully register");
},
error: function (data) {
alert("error");
}
});
}
});
[WebMethod]
public string Registering(string user3gmail, string pass3, string name3, string nickname3, string birth)
{
return "{\"registerPachage\":{\"Id\":26}}";
}
我的尝试:
我是Ajax Jquery的初学者,我正在锻炼以提高我对它的了解。我的问题是当我点击#btnRegister它的打印错误而不是成功消息。我认为我在ajax上传递的参数存在问题,但我不知道它是什么。
What I have tried:
I'm a beginner in Ajax Jquery and I'm doing exercise to improve my knowledge about it. My problem is when I click #btnRegister it's print error not Successfully message . I think there's a problem in the parameters I passed on the ajax but I don't know what is it.
推荐答案
(document).ready(function(){
(document).ready(function () {
(#btnRegister)。click(function(){
Register();
});
function Register( ){
var obj = {名字:
("#btnRegister").click(function () { Register(); }); function Register() { var obj = { Firstname:
(#txtFirstname)。val(),姓氏:
("#txtFirstname").val(), Lastname:
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