如何通过ctrl + alt + l键的组合生成中断。？ [英] How to generateinterrupt by the combination of ctrl+alt+l key.?
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问题描述
在 C中编写一个TSR程序，它将清除屏幕上的所有内容并打印您的VU ID和名称（BC0000000-名称）在视频文本存储器的中心位于0xB8000000，只要Alt + Ctrl + D组合 按从键盘。
请注意，在清除屏幕之前，您必须备份视频文本内存的内容。并且，只要Alt + Ctrl + R组合从按 键盘，视频文本内存的所有内容应该恢复。
此问题的代码：
问题出现在代码的末尾键盘中断
// CLRSCREEN和角色打印程序
#include< DOS.H>
#include< stdio.h>
void interrupt（* old）（）;
void interrupt scrnsvr（）;
// void interrupt（* oldkey）（）;
// void interrupt newkey（）;
// void cls（）; SALMAN HAIDER
unsigned char far * scr =（unsigned char 远*）0xb8000680;
unsigned char far * src =（unsigned char far *）0xb8000000;
unsigned char far * sch =（unsigned char far *）0x00400017;
int i，j;
char charsrc [ 4000 ];
void interrupt scrnsvr（）{
// 保存内容
for （i = 0 ; i < 4000 ; i ++）
charsrc [i] = *（SRC + I）;
// 清算屏幕
for （i = 0 ; i < 4000 ; i + = 2 ）
{
*（src + i）= 0x20;
*（src + i + 1 ）= 0x07;
}
}
// 在图形文本内存中心打印RollNo和Name
void charPrint（）{
* scr = 0x6D;
*（scr + 1）= 0x70;
*（scr + 2）= 0x63;
*（scr + 3）= 0x07;
*（scr + 4）= 0x31;
*（scr + 5）= 0x07;
*（scr + 6）= 0x34;
*（scr + 7）= 0x07;
*（scr + 8）= 0x30;
*（scr + 9）= 0x07;
*（scr + 10）= 0x34;
*（scr + 11）= 0x07;
*（scr + 12）= 0x30;
*（scr + 13）= 0x07;
*（scr + 14）= 0x32;
*（scr + 15）= 0x07;
*（scr + 16）= 0x32;
*（scr + 17）= 0x07;
*（scr + 18）= 0x39;
*（scr + 19）= 0x07;
*（scr + 20）= 0x37;
*（scr + 159）= 0x07;
*（scr + 160）= 0x53;
*（scr + 161）= 0x07;
*（scr + 162）= 0x61;
*（scr + 163）= 0x07;
*（scr + 164）= 0x6C;
*（scr + 165）= 0x07;
*（scr + 166）= 0x6D;
*（scr + 167）= 0x07;
*（scr + 168）= 0x61;
*（scr + 169）= 0x07;
*（scr + 170）= 0x6E;
*（scr + 171）= 0x07;
*（scr + 172）= 0x20;
*（scr + 173）= 0x07;
*（scr + 174）= 0x48;
*（scr + 175）= 0x07;
*（scr + 176）= 0x61;
*（scr + 177）= 0x07;
*（scr + 178）= 0x69;
*（scr + 179）= 0x07;
*（scr + 180）= 0x64;
*（scr + 181）= 0x07;
*（scr + 182）= 0x65;
*（scr + 183）= 0x07;
*（scr + 184）= 0x72;
}
void restore（）{
for （j = 0 ; j < 4000 ; j ++ ）
*（src + j）= charsrc [j];
}
/ *
void interrupt newkey（）{
* sch = 24;
*（sch + 1）= 34;
geninterrupt（0x65）;
charPrint（）;
（* oldkey）（）;
* /
void main（）{
// Cls
// oldkey = getvect（0x09）;
// setvect（0x09，newkey）;
old = getvect（0x65）;
setvect（0x65，scrnsvr）;
keep（ 0 ， 1000 ）;
// 功能
_AH = 0x09;
if （_ AL == 0x1D&& _AL == 0x38&& _AL == 0x20）
{
geninterrupt（0x65）中;
charPrint（）;
}
其他 如果（_ AL == 0x1D&& _AL = = 0x38&& _AL == 0x13）
{
restore（）;
}
}
}
我尝试了什么：
我多次尝试将键盘按键的扫描码放在啊但是失败了请纠正我的代码。
解决方案
请参阅我对问题的评论，这是答案的主要部分。有关BIOS中断，请参阅： INT 16H - 维基百科，免费的百科全书 [ ^ ]。
在这个级别上，你可以在键盘扫描码的水平上工作。
正如我已经在我的评论中试图解释的那样，生成中断是荒谬的。这不是事情的运作方式。对于某些教育，请参阅：控制反转 - 维基百科，免费的百科全书 [ ^ ]。
-SA
Write a TSR program in C that will clear all the contents of the screen and print your VU ID and Name (BC0000000-Name) at the center of the video text memory available at 0xB8000000 whenever Alt+Ctrl+D combination is pressed from keyboard.
Note that you have to take the backup of the contents of video text memory before clearing the screen. And, whenever Alt+Ctrl+R combination is pressed from the keyboard, all the contents of video text memory should be restored.
My Code for this Problem:
Problem occurs at the end of the code for keyboard interrupt
//CLRSCREEN AND Character Printing Program
#include<DOS.H>
#include<stdio.h>
void interrupt (*old)();
void interrupt scrnsvr();
//void interrupt (*oldkey)();
//void interrupt newkey();
//void cls(); SALMAN HAIDER
unsigned char far *scr = (unsigned char far*)0xb8000680;
unsigned char far *src = (unsigned char far*)0xb8000000;
unsigned char far *sch = (unsigned char far*)0x00400017;
int i,j;
char charsrc[4000];
void interrupt scrnsvr(){
//saving contents
for(i=0; i < 4000; i++)
charsrc[i] = *(src+i);
//Clearing Screen
for(i=0; i < 4000; i+=2)
{
*(src + i) = 0x20;
*(src + i + 1) = 0x07;
}
}
//Prints RollNo and Name at Center of Graphics Text Memory
void charPrint(){
*scr = 0x6D;
*(scr+1) = 0x70;
*(scr+2) = 0x63;
*(scr+3) = 0x07;
*(scr+4) = 0x31;
*(scr+5) = 0x07;
*(scr+6) = 0x34;
*(scr+7) = 0x07;
*(scr+8) = 0x30;
*(scr+9) = 0x07;
*(scr+10) = 0x34;
*(scr+11) = 0x07;
*(scr+12) = 0x30;
*(scr+13) = 0x07;
*(scr+14) = 0x32;
*(scr+15) = 0x07;
*(scr+16) = 0x32;
*(scr+17) = 0x07;
*(scr+18) = 0x39;
*(scr+19) = 0x07;
*(scr+20) = 0x37;
*(scr+159) = 0x07;
*(scr+160) = 0x53;
*(scr+161) = 0x07;
*(scr+162) = 0x61;
*(scr+163) = 0x07;
*(scr+164) = 0x6C;
*(scr+165) = 0x07;
*(scr+166) = 0x6D;
*(scr+167) = 0x07;
*(scr+168) = 0x61;
*(scr+169) = 0x07;
*(scr+170) = 0x6E;
*(scr+171) = 0x07;
*(scr+172) = 0x20;
*(scr+173) = 0x07;
*(scr+174) = 0x48;
*(scr+175) = 0x07;
*(scr+176) = 0x61;
*(scr+177) = 0x07;
*(scr+178) = 0x69;
*(scr+179) = 0x07;
*(scr+180) = 0x64;
*(scr+181) = 0x07;
*(scr+182) = 0x65;
*(scr+183) = 0x07;
*(scr+184) = 0x72;
}
void restore(){
for(j=0; j < 4000; j++)
*(src + j) = charsrc[j];
}
/*
void interrupt newkey(){
*sch = 24;
*(sch+1) = 34;
geninterrupt(0x65);
charPrint();
(*oldkey)();
*/
void main(){
//Cls
// oldkey = getvect(0x09);
// setvect(0x09, newkey);
old = getvect(0x65);
setvect(0x65,scrnsvr);
keep(0,1000);
//Function
_AH = 0x09;
if(_AL==0x1D && _AL==0x38 && _AL==0x20)
{
geninterrupt(0x65);
charPrint();
}
else if(_AL==0x1D && _AL==0x38 && _AL==0x13)
{
restore();
}
}
}
What I have tried:
I tried many times to put the scan code of Keyboard buttons in Ah but failed please correct me the code.
解决方案
Please see my comment to the question, which is the major part of the answer. For BIOS interrupt, please see: INT 16H — Wikipedia, the free encyclopedia[^].
On this level, you can work at the level of keyboard scan codes.
As I already tried to explain in my comment, "generate interrupt" is absurd. This is not how things work. For some education, see also: Inversion of control — Wikipedia, the free encyclopedia[^].
—SA
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