如何混合2个字符串C＃ [英] How can I mix 2 strings C#

问题描述

  string  k =   ABC; 
  string  l =   DEF; 
  string  result =   ADBECF; 

 使用系统; 
 
 命名空间 ADP_PG2_1_Solution 
 {
  public   class  MixStringsExercise 
 {
  public   static   string  MixStrings（ string  s， string  t）{
  //  示例：s = ABC，t = DEF ==> ADBECF  
  string  L; 
  string  next; 
  if （s.Length == t.Length）{
 L = s + t; 
} 其他 {
  return  空; 
} 
  for （ int  i =  0 ; i <  = s.Length; i ++）{
  return  s = 
} 
 
 
  return   null < /跨度>; 
} 
} 
} 

解决方案

这个问题虽然没有意义但是，字符串结果看起来好像你想从每个中使用1个字符然后通过递增计数器并从两个字符数组（，其中，字符串）附加下一个字符来获得结果。

  var  builder =  new  StringBuilder（）; 
  string  a =   ABC，b =   DEF; 
 
  for （ int  i =  0 ; i <  a.Length; i ++）{
 builder.Append（a [i]）; 
 builder.Append（b [i]）; 
} 
 
 Console.WriteLine（builder.ToString（））; 
 
  //  输出： 
  //   ADBECF  

我用过的StringBuilder（正如谢尔盖在解决方案1的评论中所建议的那样）获得更好的性能，因为我不必担心这里的连接。然而，该算法仍然存在一些问题，因为它适用于相同长度的数组; 尝试使用索引较少的数组。

您可以选择连接两个字符串：

  string  s1 =   ABC ; 
  string  s2 =   DEF; 
 
  //  使用+运算符 
  string  r1 = s1 + s2; 
 
  //  使用String.Concat  
  string  r2 =  String  .Concat（s1，s2）; 
 
  //  使用String.Format  
  string  r3 =  String  .Format（  {0} {1}，s1，s2）; 
 
  //  使用字符串文字（C＃5） 
 < span class =code-keyword> string  r4 = 

{S1} {S2};

// 使用StringBuilder（这个简单的任务有点矫枉过正）
string r5 = new StringBuilder（s1.Length + s2.Length）.Append（s1 ）.Append（s2）.ToString（）;

你也可以在缓冲区中逐个复制字符。

  char  [] chars =  new   char （s1.Length + s2.Length）; 
  int  index =  0 ; 
  for （ int  i =  0 ; i <  s1.Length; i ++）{
 chars [index ++] = s1 [i]; 
} 
  for （ int  i =  0 ; i <  s2.Length; i ++）{
 chars [index ++] = s2 [i]; 
} 
  string  r6 =  new  字符串（字符）; 

很抱歉我误读了你的问题。您可以通过稍微修改上面的代码块来实现它：

  char  [] chars =  new   char （s1.Length + s2.Length）; 
  int  index =  0 ; 
  for （ int  i =  0 ; i <  s1.Length; i ++）{
 chars [index] = s1 [i]; 
 index + =  2 ; 
} 
 index =  1 ; 
  for （ int  i =  0 ; i <  s2.Length; i ++）{
 chars [index] = s2 [i]; 
 index + =  2 ; 
} 
  string  output =  new  字符串（字符）; 

string k = "ABC"; 
string l = "DEF"; 
string result = "ADBECF";

using System;

namespace ADP_PG2_1_Solution
{
	public class MixStringsExercise
	{
		public static string MixStrings(string s, string t) {
			//Example : s= ABC, t = DEF ==> ADBECF 
			string L ;
			string next ;
			if (s.Length == t.Length) {
				L = s + t;
					} else {
						return null;
						}
						for(int i = 0; i <= s.Length; i ++ ){
				return s = 
							}
				
		
			return null;
		}
	}
}

解决方案

The question although makes no sense, however, the string results seem as if you want to use 1 character from each and then get the result by incrementing the counter and appending the next characters from both arrays of characters (which, strings are).

var builder = new StringBuilder();
string a = "ABC", b = "DEF";

for (int i = 0; i < a.Length; i++) {
   builder.Append(a[i]);
   builder.Append(b[i]);
}

Console.WriteLine(builder.ToString());

// Output:
// ADBECF

I used StringBuilder (as Sergey had suggested in the comments to Solution 1) to get a better performance because I don't have to worry about the concatenation here. However, the algorithm still has some problems because it works on arrays of same length; try to use an array with less indices.

You have several choices to concat two strings:

string s1 = "ABC";
string s2 = "DEF";

// Using + operator
string r1 = s1 + s2;

// Using String.Concat
string r2 = String.Concat(s1, s2);

// Using String.Format
string r3 = String.Format("{0}{1}", s1, s2);

// Using string literal (C# 5)
string r4 =

"{s1}{s2}"; // Using a StringBuilder (a bit overkill for this trivial task) string r5 = new StringBuilder(s1.Length + s2.Length).Append(s1).Append(s2).ToString();

You can also copy the characters one by one in a buffer.

char[] chars = new char(s1.Length + s2.Length);
int index = 0;
for (int i = 0; i < s1.Length; i++) {
   chars[index++] = s1[i];
}
for (int i = 0; i < s2.Length; i++) {
   chars[index++] = s2[i];
}
string r6 = new String(chars);

[Edit] Sorry for I misread your question. You can achieve it bu only slightly modifying the code block above:

char[] chars = new char(s1.Length + s2.Length);
int index = 0;
for (int i = 0; i < s1.Length; i++) {
   chars[index] = s1[i];
   index += 2;
}
index = 1;
for (int i = 0; i < s2.Length; i++) {
   chars[index] = s2[i];
   index += 2;
}
string output = new String(chars);

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