当用户输入一个数字并在list.if值中搜索时，列表如何工作，程序终止，如果找不到，则找不到输出 [英] How a list works when user enters a number and that is searched for in the list.if value found, the program terminates and if not found outputs not found

问题描述

MaxIndex=7#The maximum amount of numbers
SearchValue=input("Please enter value")#The value user inputs
Found=False#Initially found set to false
Index=0
MyList=['25','34','98','7','41','19','5']
while Index:
    if (Found==True)or(Index>=SearchValue):#The program terminates with this condition
        
    Index=Index+1
    if MyList['25','34','98','7','41','19','5']==SearchValue:
        Found=True
        print("The value found at location",Index)
    else:
        print("Value not found")

我尝试了什么：



我试过给一个真假条件，但程序始终给出未找到值条件

What I have tried:

I tried giving a true and false condition but the program always gives " Value not found"condition

推荐答案

转到索引& mdash; Python 3.3.6文档 [ ^ ]并研究如何使用列表。

Go to Index — Python 3.3.6 documentation[^] and study how to use lists.

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