请绘制此fork代码的进程树 [英] Please draw the process tree for this fork code

问题描述

#include <stdio.h>
#include <unistd.h>

main()
{
    int ii=0;

    if (fork() > 0) ii++;

    wait(NULL);

    if (fork() == 0) ii++;

    wait(NULL);

    if (fork() < 0) ii++;

    wait(NULL);

    printf ("Result = %d \n",ii);
}

我的尝试：



i试图为这个人下载一个应用程序，但我没有找到。

What I have tried:

i tried to download an application for this person but i didn't find.

推荐答案

主要进程将分叉三次：

• 第一个分叉本身会分叉两次。
• 第二个分叉本身会分叉一次。
• 第三个分叉将不再分叉。

The main process will be forked three times:

• The first fork will be itself forked two times.
• The second fork will be itself forked one time.
• The third fork will not be forked anymore.

Nope。我们不是来为你工作。

Nope. We're not here to do your work for you.

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