如何在连接mysql数据库时更新数据库? [英] How do I update the database in the connecting to mysql database?

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问题描述

我的数据库名称= loginapp

表名=用户



而不是更新数据是我的sql添加一行






包括functions.php;

?>

if(isset($ _ POST ['submit'])){



UpdateTable();

}



?>







< html>



< head>



< title> ;这是登录页面< / title>

< link rel =stylesheethref =https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min .css>

< / head>





< body>



MY database name = loginapp
table name = users

rather that updating the data it is adding a row to my sql



include "functions.php";
?>
if(isset($_POST['submit'])){

UpdateTable();
}

?>



<html>

<head>

<title> THis is the login page </title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" >
</head>


<body>













< form action =login_update.phpmethod =post>






<form action="login_update.php" method="post">



< label for =username>用户名< / label>

<输入类型=textname =usernameclass =form-control>


<label for="username">Username</label>
<input type="text" name="username" class="form-control">












< label for =password>密码< / label>

< input type = passwordname =passwordclass =form-control>


<label for="password">Password</label>
<input type="password" name="password" class="form-control">











< select name = idid =>





showAllData();

?>











< / select>





<select name="id" id="">


showAllData();
?>





</select>





< input class =btn btn-primary type =submitname =registervalue =UPDATE>



< / form>





<input class="btn btn-primary" type="submit" name="register" value="UPDATE">

</form>











< / body> < br $> b $ b

< / html>



我的尝试:



i尝试了所有程序以及UPDATING,但看起来它像INSERT命令一样工作。



</body>

</html>

What I have tried:

i have tried all the procedures along with UPDATING but looks like it is working like a INSERT command.

推荐答案

_POST ['submit'])){



UpdateTable();

}



?>







< html>



< head>



< title>这是登录页面< / title>

< link rel =stylesheethref =https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min .css>

< / head>





< body>



_POST['submit'])){

UpdateTable();
}

?>



<html>

<head>

<title> THis is the login page </title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" >
</head>


<body>













< form action =login_update.phpmethod =post>






<form action="login_update.php" method="post">



< label for =username>用户名< / label>

<输入类型=textname =usernameclass =form-control>


<label for="username">Username</label>
<input type="text" name="username" class="form-control">












< label for =password>密码< / label>

< input type = passwordname =passwordclass =form-control>


<label for="password">Password</label>
<input type="password" name="password" class="form-control">











< select name = idid =>





showAllData();

?>











< / select>





<select name="id" id="">


showAllData();
?>





</select>





< input class =btn btn-primary type =submitname =registervalue =UPDATE>



< / form>





<input class="btn btn-primary" type="submit" name="register" value="UPDATE">

</form>











< / body> < br $> b $ b

< / html>



我的尝试:



i已经尝试了所有程序以及UPDATING,但看起来它的工作方式类似于INSERT命令。



</body>

</html>

What I have tried:

i have tried all the procedures along with UPDATING but looks like it is working like a INSERT command.


代码的位置在哪里UpdateTable()方法?



这是非常非常简单的解决方案。编写UPDATE语句而不是INSERT语句。
Where is the code for the UpdateTable() method?

This is very, very, easy solution. Write an UPDATE statement instead of an INSERT statement.


这篇关于如何在连接mysql数据库时更新数据库?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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