创建一个派生自字符串构建器的类,以附加任意数量的字符串 [英] Create a class that derives from string builder to append any number of strings
问题描述
我想创建一个派生自字符串构建器的类,以附加任意数量的字符串。
我的程序应允许用户输入自己的字符串数量
示例用法:
i want to create a class that derives from string builder to append any number of strings.
My Program shoul allow the user input their own number of strings
example usage:
//Format Post Data
StringBuilder postData = new StringBuilder();
postData.Append("dst");
postData.Append("&popup=true");
postData.Append(String.Format("&username={0}", USERNAME_Validate1));// reads username from username textbox
postData.Append(String.Format("&password={0}", PASSWORD_Validate1));// reads password from password textbox
//Write Post Data To Server
using (StreamWriter writer = new StreamWriter(request.GetRequestStream()))
writer.Write(postData);
我尝试了什么:
i能够在代码中附加带字符串构建器的字符串,但我希望用户能够指定自己的字符串。
What I have tried:
i am able to append string with string builder inside the code but i want the user to be able to specify their own.
推荐答案
你不能。
你不能从StringBuilder派生,它是一个密封的
类: MSDN StringBuilder [ ^ ]
你必须封装它:创建一个包含内部私有StringBuilder的新类,并公开所有必要的方法你自己。
You can't.
You cannot derive from StringBuilder, it is asealed
class: MSDN StringBuilder[^]
You will have to encapsulate it: create a new class which contains an internal private StringBuilder, and expose all the necessary methods yourself.
除了完全有效的解决方案1之外,你还可以在StringBuilder类上创建扩展方法。
类似于:
In addition to the perfectly valid Solution 1, you also have the ability to create extension methods on the StringBuilder class.
Something like:
public static class Utility
{
public static StringBuilder AppendAnyNumberOfStrings(this StringBuilder sb, params string elements) {
foreach (string element in elements) {
sb.Append(element);
}
return sb;
}
}
并且StringBuilder类已经有一个 AppendFormat
方法删除了需要在附加
中使用 String.Format
方法。
StringBuilder.AppendFormat方法 [ ^ ]
希望这会有所帮助。
And the StringBuilder class already has an AppendFormat
method which removes the need to use the String.Format
method inside the Append
one.
StringBuilder.AppendFormat method[^]
Hope this helps.
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