如何传递2d数组并打印员工年龄，身份和工资 [英] How to pass 2d arrays and print the employee age, id, and salary

问题描述

您好，



我正在研究2D阵列，实际上我的代码正在运行，但我很难显示年龄，ID和我在主要功能中实施的薪水，

所以当我运行程序时，它只显示平均年龄和平均工资。

谢谢你的时间并帮助

这是我的代码

Hello ,

I'm working on 2d arrays and actually my code is working, but i'm having hard time to diplay the Age, ID , and salary as i implemented inside the main function,
so When i run the program it's only display the average age and the average salary.
Thank you for your time and help
here's my code

#include <iostream>
#include <cmath>
#include <math.h>
#include <string>

using namespace std;


class Employee {

public:
	Employee();//construct
	void setAge(int x) {
		age = x; 
	};
	int Employee::getAge() {
		return age;
	};

	void setId(int x) {
		id = x;
	};
	int Employee::getId() {
		return id;
	};
	void setSalary(float x) {
		salary = x;
	};
	float Employee::getSalary() {
		return salary;
	};
	void PrintEmployee(Employee arg1[][3], int arg2, int arg3);
private:
	int age; 
	int id; 
	float salary; 

};
Employee::Employee() {
		 age = 0;
		id = 0;
		 salary = 0.0;
};

void Employee::PrintEmployee(Employee arg1[][3], int arg2, int arg3) {

	int totalage = 0; ;
	int  totalsalary = 0;
	float avargeAge = 0; 
	float avargeSalary = 0; 
	    for (int row = 0; row < arg2; row++) {
		for (int colm = 0; colm < arg3; colm++) {

			totalage = totalage + arg1[row][colm].getAge();
			totalsalary = totalsalary + arg1[row][colm].getSalary();
			avargeAge = (totalage / 6);
			avargeSalary= (totalsalary / 6);

		}
	}
	
		cout << " The Average age is " << avargeAge << endl;
		cout << " The Average salary is " << avargeSalary << endl;

}


int main() {


	Employee x[2][3];
	Employee object;



	x[0][0].setAge(30); x[0][0].setId(111); x[0][0].setSalary(30000);
	x[0][1].setAge(31); x[0][1].setId(112); x[0][1].setSalary(31000);
	x[0][2].setAge(32); x[0][2].setId(113); x[0][2].setSalary(32000);
	x[1][0].setAge(33); x[1][0].setId(114); x[1][0].setSalary(33000);
	x[1][1].setAge(34); x[1][1].setId(115); x[1][1].setSalary(34000);
	x[1][2].setAge(35); x[1][2].setId(116); x[1][2].setSalary(35000);

	object.PrintEmployee(x, 2, 3);

	system("pause");
	return 0;
}

我的尝试：



当我运行程序时，它只显示平均年龄和平均工资。

我也希望程序显示表格以显示年龄，身份证和工资



感谢您的时间和帮助

What I have tried:

When i run the program it's only display the average age and the average salary.
also i want the program to display the table to show the Age, ID , and Salary

Thank you for your time and help

推荐答案

为了显示每个人的年龄和薪水，您还需要使用您显示的内部循环内的 cout 。您已完成计算。



另请参阅：基本输入/输出 - C ++教程 [ ^ ]。



在本文中，特别是阅读有关换行符的说明（通过在末尾添加换行符搜索） - 您需要在行之间换行。 br />


请注意，如果要正确对齐列，整个想法不适合该任务;只有当你知道所有字段的字符串长度并且可以选择使用 \t 时，它才有可能;在所有情况下，都会产生难看的结果。表格格式化的最简单方法是生成带有表元素的HTML代码，您可以使用任何Web浏览器将其重定向到文件和视图。或者您必须编写GUI。

-SA

To show everyone's age and salary, you also need to use your cout inside the inner loop you've shown. You already done the calculations.

See also: Basic Input/Output - C++ Tutorials[^].

In this article, in particular, read the explanation about line breaks (search by "add line breaks at the end") — you will need line breaks between rows.

Note that the whole idea is not suitable to the task if you want to align columns properly; it's possible only if you know the string lengths of all fields and optionally use \t; in all cases, expect ugly result. The simplest way of nice formatting of the table would be generating, for example, HTML code with the table elements, which you can redirect to a file and view using any Web browser. Or you would have to write a GUI.

—SA

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