如何实现tail -n linux命令 [英] How to implement tail -n linux command

问题描述

我尝试实现tail -n函数，但效率不高，你能帮助我以另一种方式实现吗？这是我的代码



函数必须显示文件的最后n行

谢谢！



我尝试过：

I try to implement tail -n function, but it is not efficiently, can you help me to implement in another way ? This is my code

function must display the last n lines of the file
Thanks!

What I have tried:

void tail_n(){
	m=atoi(params[2]);
	file_name1=fopen(params[3],"r");
	if ( file_name1 != NULL )
   	{
		while (fgets(line, 199, file_name1) != NULL)
		{
			count++;// numarul de linii din fisier
			
		}

		count1=count-m;// nr de linii de unde incep afisarea
		
	file_name1=fopen(params[3],"r");
	if(file_name1 !=NULL)
	{
		while (fgets(line,199,file_name1)!=NULL)
		{
			
			if(afisare>=count1)
				printf("%s",line);
			afisare++;
			
		}
		count=0;  count1=0;
	}
	else perror("Eroare");
   	}
   	else perror("Eroare");
	fclose ( file_name1 );;

推荐答案

为什么要打开文件两次（即使打开文件也只关闭一次）失败了）？



你应该看一下倒带 - C ++参考 [ ^ ]功能。



为了加快执行速度，您还可以使用 m 项目分配一个环形缓冲区来存储行位置。然后你可以使用 fseek - C ++ Reference [ ^ ]最低位置跳转到要打印的第一行。



未经测试的片段：

Why do you open the file twice (and close it only once even when opening fails)?

You should have a look at the rewind - C++ Reference[^] function.

To speed up execution you can also allocate a ring buffer with m items to store the line positions. Then you can use fseek - C++ Reference[^] with the lowest position to jump to the first line to be printed out.

Untested snippet:

long int *positions = (long int *)malloc(m * sizeof(long int));
int pos = 0;
int last_pos = 0;
positions[0] = 0;
while (fgets(line, 199, file_name1) != NULL)
{
    if (++pos >= m)
        pos = 0;
    positions[pos] = ftell(file_name1);
    last_pos = pos;
    count++;
}
if (count < m || ++last_pos >= m)
    last_pos = 0;
fseek(file_name1, positions[last_pos], SEEK_SET);
while (fgets(line, 199, file_name1) != NULL)
{
    printf("%s",line);
}
free(positions);

您已在 tail -c命令linux，用c实现 [ ^ ]。请不要重新发布。

You already posted this question at tail -c command linux, implement with c[^]. Please do not repost.

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