如何在网格视图中显示按钮 [英] how to display a button inside grid view
本文介绍了如何在网格视图中显示按钮的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
您好b $ b
感谢您的回复。
我们正在使用Gridview,因为我有一个按钮和一个文本当我们点击按钮时,文本必须是可见的,如何使用javascript或jquery来执行它。
谢谢&问候
Lakshman
解决方案
您可以按以下方式添加按钮和文本框,以便在单击按钮文本框时显示:
< asp:content id = BodyContent contentplaceholderid = MainContent runat = server xmlns:asp = #unknown >
< div class = jumbotron >
< asp:gridview < span class =code-attribute> autogeneratecolumns = false id = gdv1 runat = 服务器 >
< c olumns >
< asp:boundfield datafield = ID / >
< asp:boundfield datafield = FirstName / >
< asp:boundfield 数据字段 = LastName / >
< asp:templatefield >
< ; itemtemplate >
< 输入 type = text id = <% #Eval(ID)%> 隐藏 = hidden < span class =code-attribute> / >
< / itemtemplate >
< / asp:templatefield >
< asp:templatefield >
< itemtemplate >
< 输入 类型 = 按钮 value = show onclick = 显示(此) / >
< / itemtemplate >
< / asp:templatefield >
< / columns >
< / asp:gridview >
< / div >
< script type = text / javascript >
function 显示(e){
row =
(e).parent().siblings( < span class =code-string>)。find(' input') ;
Hi
Thank you for Reply.
We are using Gridview in that i have one button and one text box when ever we click button that text must be visible how to do it using javascript or jquery.
Thanks & Regards
Lakshman
解决方案
You can add button and textbox in the following manner so that when click on button textbox will be shown:
<asp:content id="BodyContent" contentplaceholderid="MainContent" runat="server" xmlns:asp="#unknown"> <div class="jumbotron"> <asp:gridview autogeneratecolumns="false" id="gdv1" runat="server"> <columns> <asp:boundfield datafield="ID" /> <asp:boundfield datafield="FirstName" /> <asp:boundfield datafield="LastName" /> <asp:templatefield> <itemtemplate> <input type="text" id="<%#Eval("ID") %>" hidden="hidden" /> </itemtemplate> </asp:templatefield> <asp:templatefield> <itemtemplate> <input type="button" value="show" onclick="Show(this)" /> </itemtemplate> </asp:templatefield> </columns> </asp:gridview> </div> <script type="text/javascript"> function Show(e) {
row =
(e).parent().siblings("").find('input');
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