直接创建指向数组的数组指针。 [英] Directly creating a array pointer to an array.

问题描述

我是C的新手。



创建一个数组，在每个索引处保存指向另一个动态大小数组的指针。

I'm new to C.

Create an array which holds at every index a pointer to another array of dynamic size.

int main()
{
  unsigned int i , j;

  int* array1[2];
  int a1[] = {1,2,3};
  int a2[] = {2,3};

  array1[0] = a1;
  array1[1] = a2;

  for (i=0 ; i < 2; i++) {
     printf("The value of array1[%d] = %d" , i , *array1[i]);
  }

  return 1;
}

array1的值[0] = 1



array1的值[1] = 2





但同样直接这样做会导致错误。

the value of array1[0] = 1

the value of array1[1] = 2


But similarly doing it directly ,Causing an error.

unsigned int* c[3];
 c[0] = {0, 5, 4, 7};  //  This Line Err` 
 c[1] = {0, 5, 4, 3, 2, 6, 7};
 c[2] = {0, 5, 4, 3, 2};

导致错误：文件try.c line xx function main：`{'
之前的语法错误


为什么？



谢谢

Causing an error : file try.c line xx function main: syntax error before `{'

Why ??

thanks

推荐答案

{1,2,3} 语法。一般分配不允许这样做。

The {1, 2, 3} syntax is allowed only when initializing during the array's definition. It is not allowed for general assignment.

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