如何在派生类中创建复制构造函数 [英] How to create copy constructor in derived class

问题描述

如何在派生类中创建复制构造函数。



基类和派生类都有自己独特的成员。







基类本身有自己的复制构造函数。



我知道的解决方法是创建两个单独的类。

How do I create copy constructor in derived class.

Both base class and derived class has it's own unique members.



The base class itself has its own copy constructor defined.

The workaround I know is to create two separate classes.

推荐答案

找到解决方案。

Solution found.

class Warrior : public Human {
private:
	int		_armor;
	int		_defense;
public:
	Warrior();

	Warrior	(const int &id,
			 const int &h,
			 const int &a,
			 const int &def):
		_armor(a),
		Human(id,h)
		{}

	Warrior (const Warrior &rhs):
		Human (rhs),				// this line produces linker error before
		_armor	{v.getArmor()}
{}
//...
	
};

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