如何获取包含仅从字符串开始[和结束] [英] how to get contain start with [ and end with ] only from string

问题描述

如何从[和结束]开始包含仅来自字符串





[ANC 2 DATE] = [yes]和[AllIFADone] = [YES]和



i想要在阵列中出来



喜欢

[ANC 2 DATE]

[是]

[AllIFADone]



其他应该得到忽略

how to get contain start with [ and end with ] only from string


[ANC 2 DATE] = [yes] AND [AllIFADone] = [YES] AND

i want out out in array

like
[ANC 2 DATE]
[yes]
[AllIFADone]

other should get ignore

推荐答案

会员-515487的解决方案可行，但平衡组的使用更好：

Member-515487's solution will work, but the use of Balancing Groups is a better idea:

(?<sb>\[).*?(?<-sb>\])

这可以不用使用RegEx：

This can be done without using RegEx:

char[] splitChars = new[] { '[' };

string anc = @"[ANC 2 DATE] = [yes] AND [AllIFADone] = [YES] AND";

string[] ancSplit = anc.Split(splitChars, StringSplitOptions.RemoveEmptyEntries)
    .Select(strx => ('[' + strx.Substring(0, strx.IndexOf(']') + 1))).ToArray();

但是，我没有声称这样做比使用RegEx要好。



样本结果：

However, I am not claiming that doing it this way is better than using a RegEx.

Sample result:

? ancSplit
{string[4]}
    [0]: "[ANC 2 DATE]"
    [1]: "[yes]"
    [2]: "[AllIFADone]"
    [3]: "[YES]"

string str = "[ANC 2 DATE] = [yes] AND [AllIFADone] = [YES] AND ";
           var pattern = @"(\[(?:.*?)\])";

           MatchCollection mcol = Regex.Matches(str, pattern);

           foreach (Match m in mcol)
           {
               Console.WriteLine(m);
           }

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