检测来自IOS或ANDROID SYSTEM等来源的请求。 [英] detect request coming from which source like IOS or ANDROID SYSTEM.

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本文介绍了检测来自IOS或ANDROID SYSTEM等来源的请求。的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如何检测来自IOS或ANDROID SYSTEM等来源的请求。



例如如果请求来自IPHONE那么返回IOS

如果请求来自ANDROID PHONE那么返回ANDRO>



请根据上述要求提供我的代码。



谢谢

How to detect request coming from which source like IOS or ANDROID SYSTEM.

FOR EXAMPLE IF REQUEST IS COMING FROM IPHONE THEN RETURN IOS
IF REQUEST IS COMING FROM ANDROID PHONE THEN RETURN ANDROID

PLEASE GIVE ME CODE FOR ABOVE REQUIREMENT.

THANKS

推荐答案

检查如何:检测ASP.NET Web窗体中的浏览器类型和浏览器功能 [ ^ ]

check How to: Detect Browser Types and Browser Capabilities in ASP.NET Web Forms[^]
private void Button1_Click(object sender, System.EventArgs e)
{
    System.Web.HttpBrowserCapabilities browser = Request.Browser;
    string s = "Browser Capabilities\n"
        + "Type = "                    + browser.Type + "\n"
        + "Name = "                    + browser.Browser + "\n"
        + "Version = "                 + browser.Version + "\n"
        + "Major Version = "           + browser.MajorVersion + "\n"
        + "Minor Version = "           + browser.MinorVersion + "\n"
        + "Platform = "                + browser.Platform + "\n"
        + "Is Beta = "                 + browser.Beta + "\n"
        + "Is Crawler = "              + browser.Crawler + "\n"
        + "Is AOL = "                  + browser.AOL + "\n"
        + "Is Win16 = "                + browser.Win16 + "\n"
        + "Is Win32 = "                + browser.Win32 + "\n"
        + "Supports Frames = "         + browser.Frames + "\n"
        + "Supports Tables = "         + browser.Tables + "\n"
        + "Supports Cookies = "        + browser.Cookies + "\n"
        + "Supports VBScript = "       + browser.VBScript + "\n"
        + "Supports JavaScript = "     + 
            browser.EcmaScriptVersion.ToString() + "\n"
        + "Supports Java Applets = "   + browser.JavaApplets + "\n"
        + "Supports ActiveX Controls = " + browser.ActiveXControls 
              + "\n"
        + "Supports JavaScript Version = " +
            browser["JavaScriptVersion"] + "\n";

    TextBox1.Text = s;
}


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