如何将字符串转换为时间格式 [英] How to convert string into time format

问题描述

嗨frds，

我想以小时和分钟格式显示时间。我在110中输入小时和分钟表示它自动占用01:10 AM或01:10 PM。我不知道怎么办这个。任何人都帮助我。



谢谢

解决方案

  string  str =   110; 
  var  hr = str [ 0 ] < ;  =  9 ？   0 + str [ 0 ] ：str [ 0 ]; 
  var  min = str [ 1 ] + str [ 2 ]; 
  var  time = hr +  ：  + min; 

未经测试，但请试一试。 :)



-KR

您可以使用正则表达式解决此问题。这种方法的优点是，如果用户输入的数字不是有效时间，则内置验证。



表达式

< pre lang =text> ^（（？< hour> [0-9]）|（？< hour> [0-1] [0-9]））（？< min> [0-5] ] [0-9]）

* ^ 是起始锚点。这意味着正则表达式引擎从字符串的开头开始

* （（？< hour> [0-9]）|（？< hour> [0-1] [0-9]））表示0-9之间的单个数字或两个数字，其中第一个数字必须为0或1.

？< hour> 是一个命名组，可以让以后轻松提取部分正则表达式。

* （？< minute> [0-5] [0-9]）表示匹配两位数，其中第一位必须在0-5范围内，第二位0-9位于>范围内。 00 - 59.

*

Hi frds,
I want to display the time in hours and minute format. I enter the hour and minute in 110 means it automatically take 01:10 AM or 01:10 PM. I don't Know how can I proceed this. Anyone help me.

Thank You

解决方案

string str = "110";
var hr = str[0] <= 9 ? "0" + str[0] : str[0] ;
var min = str[1] + str[2];
var time = hr + ":" + min;

Not tested, but give it a try. :)

-KR

You can solve this problem with a regular expression. The advantage of this approach is that you get built in validation if the user enters numbers that is not a valid time.

Expression

^((?<hour>[0-9])|(?<hour>[0-1][0-9]))(?<minute>[0-5][0-9])

* ^ is the start anchor. It means that the regex engine starts at the beginning of the string
* ((?<hour>[0-9])|(?<hour>[0-1][0-9])) means either a single digit from 0-9 or two digits where the first has to be 0 or 1.
?<hour> is a named group and makes it easy to extract parts of the regex later.
* (?<minute>[0-5][0-9]) means that two digit will be matched where the first has to be within the range 0-5 and the second 0-9 -> 00 - 59.
*

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