我有一个代码我试图添加到visual studio c ++给我一个输出，我迷失了 [英] I have a code im trying to add to visual studio c++ to give me an output and im lost

问题描述

.data

array1 DWORD 10d，20d，30d，40d，50d，60d，70d，80d，90d

.code

主要PROC

mov ESI，OFFSET array1; ESI现在指向array1的第一项

mov EDI，SIZEOF array1

添加EDI，OFFSET array1

sub EDI，TYPE array1; EDI现在指向array1的最后一项



mov ECX，LENGTHOF array1

shr ECX，1;现在ecx是array1长度的一半

L1：mov EAX，[ESI];在这个循环中我们反转数组的项目

mov EBX，[EDI]

mov [EDI]，EAX

mov [ESI]，EBX

添加ESI，TYPE array1

子EDI，类型数组1

LOOP L1



mov ECX，LENGTHOF array1;这里我们只打印数组

mov ESI，OFFSET array1

L2：MOV EAX，[ESI]

致电WriteInt

致电Crlf

添加ESI，类型数组1

LOOP L2

退出

主要ENDP

END main



这个是我必须添加到我的项目的代码，但我不知道如何将其转换为c ++工作。

.data
array1 DWORD 10d,20d,30d,40d,50d,60d,70d,80d,90d
.code
main PROC
mov ESI, OFFSET array1 ;ESI now points to the first item of array1
mov EDI, SIZEOF array1
add EDI, OFFSET array1
sub EDI, TYPE array1 ;EDI now points to the last item of array1

mov ECX, LENGTHOF array1
shr ECX, 1 ;now ecx is half the length of the array1
L1: mov EAX, [ESI] ;in this loop we reverse the items of the array
mov EBX, [EDI]
mov [EDI],EAX
mov [ESI],EBX
add ESI, TYPE array1
sub EDI, TYPE array1
LOOP L1

mov ECX, LENGTHOF array1;here we just print the array
mov ESI, OFFSET array1
L2: MOV EAX, [ESI]
call WriteInt
call Crlf
add ESI, TYPE array1
LOOP L2
exit
main ENDP
END main

This is the code i have to add to my project but im not sure how i convert it into c++ to work.

推荐答案

此代码假定您已定义_countof宏。



https://msdn.microsoft。 com / en-us / library / ms175773.aspx [ ^ ]

This code assumes you have the _countof macro defined.

https://msdn.microsoft.com/en-us/library/ms175773.aspx[^]

#include <stdio.h>

// array1 DWORD 10d,20d,30d,40d,50d,60d,70d,80d,90d

static long words[] = {10, 20, 30, 40, 50, 60, 70, 80, 90};

int main(int argc, char *argv[])
{
    // swap the array.
    unsigned count = _countof(words);
    unsigned half = _count / 2;
    for (unsigned i = 0; i < half; i++)
    {
        long swap = words[i];
        words[i] = words[count - i - 1];
        words[count - i - 1] = swap;        
    }

    // print the array.
    for (unsigned i = 0; i < half; i++)
    {
        printf(" %ld", words[i]);
    }
    return 0;
}
</stdio.h>

你知道，打印出来会更简单数字的顺序相反。

You know, it would be simpler to just print the numbers in reverse order.

#include <stdio.h>

static long words[] = {10, 20, 30, 40, 50, 60, 70, 80, 90};

int main(int argc, char *argv[])
{
    // print the array.
    unsigned i = _countof(words);
    while (i > 0)
    {
        printf(" %ld", words[--i]);
    }
    return 0;
}
</stdio.h>

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