更改功能不起作用jquery [英] change function is not working jquery

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本文介绍了更改功能不起作用jquery的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

$( document ).ready(function() {
       $(function () {
           $.ajax({
               type: "POST",
               url: "Single_page.aspx/getCity",
               data: '{}',
               contentType: "application/json; charset=utf-8",
               dataType: "json",
               success: function (r) {
                   var ddlCity = $("[id*=ddlCity]");
                   ddlCity.empty().append('<option selected="selected" value="0">Please Select City </option>');
                   $.each(r.d, function () {
                       ddlCity.append($("<option></option>").val(this['Value']).html(this['Text']));
                   });
               }
           });
       });

   });

        $('#<%=ddlCity.ClientID %>').change(function () {
           alert(cityID);
           var cityID = $("[id*=ddlCity] > option[@selected]").attr("value");
           alert(cityID);
           $("[id *= ddlLocality]").html("");
           $.ajax({
               type: "POST",
               url: "Single_page.aspx/getLocality",
               data: "{ID:'" + cityID + "'}",
               contentType: "application/json; charset=utf-8",
               dataType: "json",
               success: function (r) {
                   var ddlLocality = $("[id*=ddlLocality]");
                   ddlLocality.empty().append('<option selected="selected" value="0">Please Select City </option>');
                   $.each(r.d, function () {
                       ddlLocality.append($("<option></option>").val(this['Value']).html(this['Text']));
                   });
               }
           });
       });




<asp:DropDownList ID="ddlCity" runat="server"  class="form-control" >
                </asp:DropDownList>
                <asp:DropDownList ID="ddlLocality" runat="server" class="form-control">
                </asp:DropDownList>

推荐答案

(document).ready(function(){
( document ).ready(function() {


( function(){
(function () {


.ajax({
type:POST,
url:Single_page.aspx / getCity,
data:' {}',
contentType:application / j儿子; charset = utf-8,
dataType:json,
成功:函数(r){
var ddlCity =
.ajax({ type: "POST", url: "Single_page.aspx/getCity", data: '{}', contentType: "application/json; charset=utf-8", dataType: "json", success: function (r) { var ddlCity =


这篇关于更改功能不起作用jquery的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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