如何在每次新迭代中创建新实例 [英] How Do I Create New Instance Every New iteration

问题描述

我想创建新实例每次新迭代我都试图连接对象名称而不是错误

I Want To Create New Instance Every New iteration And I Am My Trying To concatenate Object Name Than It Throws Error

static void Main(string[] args)
     {
         int i;
         char ch = 'n';
         while(ch=='n')
         {
             for(i=0;i<=10;i++)
             {   // I Want To Create New Instance Every New iteration And My Trying To concatenate  Object Name It Throws Error
                  lern "st"+i = new lern();
             }
         }

     }
 }
 class lern
 {
     public static int i = 0;
     public int m1,m2,m3;
     public string nm, sub;
    public lern ()
     {

     }
 }

推荐答案

否，错误的方式。

在C＃中不允许在运行时创建变量名，这意味着使用C＃你的解决方案是不可能的。



您应该查看有关数组的文档和可调整大小的列出。

No, Wrong way.
In C# do not allow to create variables names at runtime, this mean that your solution is impossible with C#.

You should have a look at documentation about arrays and resizeable lists.

你不能创建这样的变量

You cannot create a variable like this

lern "st"+i = new lern();

c＃中的
。它甚至不会编译。



你必须这样做：

in c#. It will not even compile.

You have to do something like this:

List<lern> lernList = new List<lern>();
for (i=0; i<=10; i++)
{
    lernList.Add(new lern());
}

也就是说，我们必须看看你的外环。

That said, we have to take a look at your outer loop.

while (ch=='n')
{
...
}

你将如何摆脱这种循环？

你在哪里更改 ch 的值？

你不能这样做。您无法在运行时创建变量名称，因为编译器无法检查它们！即使你可以，你也不能使用它们，因为它们会在列表的末尾超出范围。



你想要做的就是使用数组或集合：

You can't do that. You can't create variable names at run time, because the compiler can't check them! Even if you could, you couldn;t use them as they would go "out of scope" at the end of the list.

What you want to do is use an array, or a collection:

private List<lern> lerns = new List<lern>();
static void Main(string[] args)
    {
    int i;
    char ch = 'n';
    while(ch=='n')
        {
        for(i=0;i<=10;i++)
            {   
            lern l = new lern();
            lerns.Add(l);
            }
        }
    }

然后在后续代码中，您可以单独引用每个实例：

Then in subsequent code you can refer to each instance separately:

lern firstLern = lerns[0];
lern lastLern = lerns[lerns.Count - 1];

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