将varchar数据类型转换为日期时间数据类型会导致超出范围的值 [英] The conversion of a varchar data type to a datetime data type resulted in an out-of-range value
本文介绍了将varchar数据类型转换为日期时间数据类型会导致超出范围的值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我的HTML代码: -
Here's My HTML Code:-
<div class="col-lg-3 col-md-3" style="float: left">
<asp:DataList runat="server" ID="dataimg" RepeatColumns="4" RepeatDirection="Horizontal" ItemStyle-CssClass="panel panel-default">
<ItemTemplate>
<li class="list-group-item list-group" style="width: 200px">
<asp:HyperLink ID="HyperLink1" NavigateUrl='<%# String.Concat("Img/",Eval("image")) %>'
Target="_blank" runat="server">
<img src='Img/<%#Eval("image") %>' alt="15aug" width="160px" height="160px" />
</asp:HyperLink>
<asp:Label ID="Label1" runat="server" CssClass="text text-default" Font-Size="12px" Text='<%#Eval("detail") %>'></asp:Label>
<%--<label id="label">
<a href="<%#"design.aspx?pid="+Eval("ID") %>">View Details</a></label>--%>
</li>
</ItemTemplate>
</asp:DataList>
</div>
C#代码: -
C# Code:-
protected void Unnamed1_Click(object sender, EventArgs e)
{
// NB: The "as" operator can return null:
LinkButton lnk = sender as LinkButton;
if (lnk == null)
{
throw new InvalidOperationException("sender is not a LinkButton!");
}
DateTime theDate;
// NB: If your date is in a specific format, use TryParseExact instead.
string format = "dd-MM-yyyy";
if (!DateTime.TryParseExact(lnk.Text, format, null, DateTimeStyles.None, out theDate))
{
// The text is not a valid date:
throw new FormatException(string.Format("The value '{0}' is not a valid date.", lnk.Text));
}
TextBox1.Text = lnk.Text;
using (SqlConnection con1 = new SqlConnection(ConfigurationManager.AppSettings["str"]))
using (SqlCommand cmd = new SqlCommand("SELECT * FROM date1 WHERE ddate = @ddate", con1))
{
cmd.Parameters.AddWithValue("@ddate", theDate.Date);
DataSet ds1 = new DataSet();
SqlDataAdapter da1 = new SqlDataAdapter(cmd);
da1.Fill(ds1);
dataimg.Visible = true;
dataimg.DataSource = ds1;
dataimg.DataBind();
}
}
推荐答案
上述错误消息的任何可能原因,你会发现此处 [ ^ ]。
Any possible reason of above error message, you'll find here[^].
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