如何以最快的方式从Xml中获取节点值? [英] How to fetch the node values from an Xml in the fastest manner ?

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问题描述

如何以最快的方式从Xml中获取节点值?

我想以最快的方式获取节点。我已经尝试使用Xml节点列表,然后使用foreach和validate从相同的循环中获取XmlNode。这很耗时。

How to fetch the node values from an Xml in the fastest manner ?
I want to fetch nodes in the most fast manner. I have tried using Xml Node List and then fetch the XmlNode from the same and loop using foreach and validate. It is time consuming.

推荐答案

最有可能的是,最快的将使用类 System.Xml.XmlReader

https:/ /msdn.microsoft.com/en-us/library/system.xml.xmlreader%28v=vs.110%29.aspx [ ^ ]



只有当您的XML非常小时,更快的方法可能是在其中进行一些 ad-hoc 字符串搜索,但我建议通过各种方式避免这些事情,原因很明显。



-SA
Most likely, the fastest will be using the class System.Xml.XmlReader:
https://msdn.microsoft.com/en-us/library/system.xml.xmlreader%28v=vs.110%29.aspx[^]

Only if your XML is extremely small, the faster method could be some ad-hoc string search in it, but I would recommend to avoid such things by all means, by pretty obvious reasons.

—SA


As Sergey Aleksandrovich Kryukov [ ^ ]提到它取决于文件大小。 对于小部分数据,即使您使用 Linq to xml [ ^ ]。



想象一下,xml结构如下:

As Sergey Aleksandrovich Kryukov[^] mentioned it depends on file size. For small portion of data the difference measured in time of reading xml file is unnoticeable, even if you use Linq to xml[^].

Imagine, an xml structure looks like:
Root
--Level1
  |--Level2
    |--Level3
      |--Level4
        |--Level5
          |--Level6
            |--Level7
              |--Level8



您希望从节点获取节点(数据) Level8 ,所以你可以使用这样的查询实现:


You want to get nodes (data) from node at Level8, so you can achieve that using query like this:

XDocument xdoc = XDocument.Load("fullfilename.xml");
var result = xdoc.Descendants("Level8")
    .Descendants()
    .Select(a=>a);





如需了解更多信息,请参阅:

LINQ to XML [ ^ ]

LINQ to XML Overview [ ^ ]

基本查询(LINQ to XML) [ ^ ]



For further information, please see:
LINQ to XML[^]
LINQ to XML Overview[^]
Basic Queries (LINQ to XML)[^]


node.SelectNodes(some some some here);

这是选择节点而没有循环概念的最快方法。
node.SelectNodes("some XPath here");
This is fastest way to select node without looping concept.


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