我将使用什么代码来运行此程序 [英] What Code Will I Put To Run This Program

问题描述

#include <stdio.h>
#include <conio.h>
#DEFINE p = printf, ps = puts;

int getFactorial(int x)
{
    //what code will i put here
}
int getFibo(int x)
{
    //what code will i put here
}
void printWord(int num)
{
    //what code will i put here
 }
 void main ()
 {
      int num;
      ps("enter a number:");
      scanf("%d", &num);
      
      p("Factorial of %d is: %d\n", num, getFactorial(num));
      p("Fibonacci of %d is: %d\n", num, getFibo(num));
      p("worded value of of %d is: ", num);
      PrintWord(num));
}

推荐答案

您知道 n 的阶乘定义这种方式（假设 n> = 1 ）

You know the factorial of n is defined this way (assume n>=1 )

fact(n) = n * (n-1) * (n-2) * ... * 1

这意味着

That means

fact(n) = n * fact(n-1)

因此，知道事实（n-1）让你简单地计算 fact（n）。使用这个想法你我写了

Hence, knowing fact(n-1) makes you simply compute fact(n). Using this idea you my write

fact(1) = 1
fact(2) = 2 * fact(1) = 2 * 1 = 2
fact(3) = 3 * fact(2) = 3 * 2 = 6
...
fact(n) = n * fact(n-1)

您可以使用简单的循环实现上述操作。



Fibonacci代码稍微详细一点。

You may implement the above operation using a simple loop.

Fibonacci code is just a bit more elaborated.

不，这里不会做家庭作业。

因为那样你会永远无法学到任何东西。



-KR

No, Homework won't be done here.
Because then you will never be able to learn anything.

-KR

你的作业是为了你学习那些东西。所以请学习 Factorials 和 Fibonacci 。



对于措辞，你必须自己建立一个字符串。您需要数字0-9和数百的辅助函数，依此类推。而且工作时，使用％运算符对数字进行反向划分以得到输出的最后一个值，然后用10除以等等。

Your homework is for you learning that stuff. So learn ablout Factorials and Fibonacci.

For the wording you must build a string yourself. You need a helper functions for the digits 0-9 and the "hundreds" and so on. And than work the number reversely divided the with % operator to get last value for output and than divide with 10 and so so.

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