如何在c＃的xml中计算每个节点中的子节点和元素的数量 [英] how to get count of child nodes and elements in each node in c# of xml

问题描述

如何获取xml文件的子节点总数和每个子节点中的总元素。[我想在运行时在表格布局控件中显示xml文件，我需要计算行和列]

如何在运行时基于xml文件获取行和列的计数。

解决方案

使用.NET中提供的XML类之一解析文件，例如 https://msdn.microsoft.com/ en-us / library / system.xml.xmldocument（v = vs.110）.aspx [ ^ ]。

看看例子：

 //定义xml文档内容
 string xcontent = @<？  xml     version   ='  1.0'   ？ >  
 < ;  表格 >  
  <  行 >  
 <   row     number   ='  0' >  
 <   col    数字  ='  1'    header   ='  true' >  <   / col  >  
 <   col     number   ='  2'    header   ='  true' >  B <   / col  >  
 <   / row  >  
 <   row    数字  ='  1' >  
 <   col     number   ='  1'   标题  ='  false' >  ValueA1 <   / col  >  
 <   col     number   ='  2'    header   ='   false' >  ValueB1 <   / col  >  
 < ;   / row  >  
 <   row     number   ='  2' >  
 <   col     number   ='  1 '    header   ='  false' >  ValueA2 <  < span class =code-leadattribute> / col  >  
 <   col     number   ='  2'   标题  ='  false' >  ValueB2 <   / col  >  
 <   / row  >  
 <   / rows  < span class =code-keyword>>  
 <   / table  > ; 
 
 //从字符串
创建xml文档XDocument xdoc = XDocument.Parse（xcontent）; 
 
 //获取元素的名称，其级别和否。子节点
 var result = xdoc.Descendants（）
 .Select（x => new 
 {
 NodeName = x.Name，
 NodeLevel = x.AncestorsAndSelf （）。Count（），
 ChildsCount = x.Descendants（）。Count（）
} 
）
 .Distinct（）; 

结果：

  NodeName NodeLevel ChildsCount  
表1 10 
行2 9 
行3 2 
 col 4 0 

您可能对 XmlElement的其他属性和方法感兴趣类 [ ^ ]。最有趣的是 XElement.AncestorsAndSelf Method（） [< a href =https://msdn.microsoft.com/en-us/library/bb346865%28v=vs.110%29.aspxtarget =_ blanktitle =New Window> ^ ]

how to get total number of child nodes of xml file and total elements in each child node.[i want to display the xml file in table layout control at run time for that i need to count rows and coloms]
how to get count of rows and colums at runtime based on xml file.

解决方案

Parse the file with one of the XML classes available in .NET, such as https://msdn.microsoft.com/en-us/library/system.xml.xmldocument(v=vs.110).aspx[^].

Have a look at example:

//define xml document content
string xcontent = @"<?xml version='1.0' ?>
        <table>
        <rows>
        <row number='0'>
            <col number='1' header='true'>A</col>
            <col number='2' header='true'>B</col>
        </row>
        <row number='1'>
            <col number='1' header='false'>ValueA1</col>
            <col number='2' header='false'>ValueB1</col>
        </row>
        <row number='2'>
            <col number='1' header='false'>ValueA2</col>
            <col number='2' header='false'>ValueB2</col>
        </row>
        </rows>
        </table>";

//create xml document from string
XDocument xdoc = XDocument.Parse(xcontent);

//get the name of element, its level and no. of subnodes
var result = xdoc.Descendants()
        .Select(x=>new
            {
                NodeName = x.Name,
                NodeLevel = x.AncestorsAndSelf().Count(),
                ChildsCount = x.Descendants().Count()
            }
        )
        .Distinct();

Result:

NodeName NodeLevel ChildsCount
table    1         10
rows     2         9
row      3         2
col      4         0

You might be interested in other properties and methods of XmlElement class[^]. A most interesting is XElement.AncestorsAndSelf Method ()[^]

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