如何在登录成功时显示警报 [英] How to display alert when login is successful
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问题描述
index.php
index.php
<html>
<script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.2.8/angular.min.js"></script>
<script src="http://cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/0.9.0/ui-bootstrap-tpls.min.js"></script>
<script src="js/script.js"></script>
<div id="container" ng-app="myApp">
<section>
<form class="form-inline" ng-controller="FormController" ng-submit="submitForm()" role="form" method="post">
<div class="form-group">
<label class="sr-only" for="Source Station">Insert Your Name</label>
<input type="text" ng-model="username" placeholder="John" class="form-control" >
</div>
<div class="form-group">
<label class="sr-only" for="Source Station">Insert Your City</label>
<input type="text" ng-model="password" placeholder="Perth" class="form-control" >
</div>
<button type="submit" class="btn btn-primary">Submit Record</button>
</form>
</section>
</div>
</html>
script.js
script.js
var App = angular.module('myApp', ['ui.bootstrap']);
function FormController($scope, $http) {
$scope.submitForm = function ()
{
console.log("posting data....");
$http({
method: 'POST',
url: 'authenticate.php',
headers: {'Content-Type': 'application/json'},
/*headers : {'Content-Type':'application/x-www-form-urlencoded; charset=UTF-8'},*/
data: JSON.stringify({username: $scope.username,password:$scope.password})
}).success(function (data){
alert(data);
console.log(data);
$scope.message = data.status;
alert(data);
alert($scope.message);
alert(data.status);
alert(data.result);
}).error(function(err){alert('aaaaa');})
};
}
和
authenticate.php
And
authenticate.php
function ob_file_callback($buffer)
{
global $ob_file;
fwrite($ob_file,$buffer);
}
$ob_file = fopen('test.txt','w');
ob_start('ob_file_callback');
$postd = file_get_contents('php://input');
$request = json_decode($postd);
//print_r($request);
$username = $request->username;
$password = $request->password;
//echo($username);
//echo($password);
if( $username=="service" && $password == "service@123" )
{
//echo $result = "{'status':'1'}";
echo $result=1;
}
else
{
//echo $result = '{"status":"2"}';
echo $result=2;
}
echo json_encode($result);
//$name= $request->name;
//$city= $request->city;
//echo json_encode($name);
//print_r ($name);
//print_r ($city);
/*//$postdata = file_get_contents('php://input');
// $request = json_decode($postdata);
// $name = $postdata->name;
// $city = $postdata->city;
//Parse error: in C:\xampp\htdocs\newaj\login.php on line 17<br />
//echo $name; */
?>
推荐答案
范围，
http）{
http) {
scope.submitForm = function （）
{
console.log（ 发布数据....）;
scope.submitForm = function () { console.log("posting data....");
这篇关于如何在登录成功时显示警报的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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