如何使用触发器处理控件的可见性属性 [英] How to handle visibility property of control with triggers

问题描述

我是WPF的新手，我创建了应用程序，我想在其中处理带触发器的Button的可见性属性。

我在我的内联样式Button中创建了触发器，当IsMouseOver属性时是的，我保持按钮隐藏的可见性。

但是当我运行应用程序并在按钮上运行我的光标时，它的可见性隐藏不会保持不变它每次我按下按钮时都会发出波动。

请帮助。

提前谢谢：）

I am new in WPF and I have created application in which i want to handle visibility property of Button with triggers.
I have created trigger inside my inline style of Button and when "IsMouseOver" property is true, I keep visibility of button hidden.
But when i run application and run my curser over button, its visibility "Hidden" doesn't stay constant it fluctuate every time i run my curser over button.
Please need help.
Thank you in advance :)

推荐答案

想想会发生什么：

Think about what happens:

1. 将鼠标移到按钮上;
2. IsMouseOver 是 true ，所以你的触发器会隐藏按钮;
3. 按钮被隐藏，所以鼠标不能超过按钮。触发器再次显示该按钮;
4. IsMouseOver 是 true ，因此您的触发器会隐藏按钮;
5. ...

1. You move the mouse over the button;
2. IsMouseOver is true, so your trigger hides the button;
3. The button is hidden, so the mouse cannot be over the button. The trigger shows the button again;
4. IsMouseOver is true, so your trigger hides the button;
5. ...

您可以尝试将按钮的不透明度设置为 0 而不是隐藏它。



然而，这听起来像是一个非常烦人且无法使用的UI设计。

You could try setting the button's Opacity to 0 instead of hiding it.

However, this sounds like an extremely annoying and unusable UI design.

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