在SQL Server 2008中查询数据 [英] Query data in SQL server 2008
本文介绍了在SQL Server 2008中查询数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
大家好!
我有一个包含此表的数据库:
#Report:链接图像表
http://prntscr.com/8h43p4 [ ^ ]
如何查询输出数据以下结果:
http://prntscr.com/8h44r5 [ ^ ]
谢谢大家!
解决方案
试试这个
DECLARE @ TBL 表
(
ID INT IDENTITY ,
REPORTDATE DATETIME ,
GAMENAME VARCHAR ( 50 ),
TO TAL INT
)
INSERT INTO @ TBL (REPORTDATE,GAMENAME,TOTAL)
SELECT ' 2015-09-05',' Ninja Runner', 2000 UNION ALL
SELECT ' < span class =code-string> 2015-09-05',' ZigZag', 1500 UNION ALL
SELECT ' 2015-09-05',' Sky Force', 8000 UNION ALL
SELECT ' 2015-09-06',' ZigZag', 300 UNION ALL
SELECT ' 2015-09 -06',' Sky Force', 2500 UNION ALL
SELECT ' 2015-09-07',' 忍者Runner', 700 UNION ALL
SELECT ' 2015-09- 07',' Sky Force', 1000 UNION ALL
SELECT ' 2015-09-08', ' ZigZag', 10000
< span class =code-keyword> SELECT TMP.REPORTDATE,TMP.GAMENAME,ISNULL(T.TOTAL, 0 )
FROM
(
SELECT distinct GAMENAME,A.REPORTDATE
FROM @ TBL
CROSS JOIN
(
SELECT ' 2015-09-03' as ' REPORTDATE' UNION ALL
SELECT ' 2015-09-04' UNION ALL
SELECT ' 2015-09-05' UNION ALL
SELECT ' 2015-09-06' UNION ALL
SELECT ' 2015-09-07' UNION ALL
SELECT ' 2015-09-08'
)A
)TMP LEFT OUTER JOIN @ TBL T ON TMP.GAMENAME = T.GAMENAME AND TMP.REPORTDATE = T.REPORTDATE
订单 按 1 , 2
从#report
Hi all!
I have a database with this table:
#Report: link image table
http://prntscr.com/8h43p4[^]
How to query output data the following results:
http://prntscr.com/8h44r5[^]
Thanks every one!解决方案Try this
DECLARE @TBL TABLE ( ID INT IDENTITY, REPORTDATE DATETIME, GAMENAME VARCHAR(50), TOTAL INT ) INSERT INTO @TBL (REPORTDATE, GAMENAME, TOTAL) SELECT '2015-09-05', 'Ninja Runner', 2000 UNION ALL SELECT '2015-09-05', 'ZigZag', 1500 UNION ALL SELECT '2015-09-05', 'Sky Force', 8000 UNION ALL SELECT '2015-09-06', 'ZigZag', 300 UNION ALL SELECT '2015-09-06', 'Sky Force', 2500 UNION ALL SELECT '2015-09-07', 'Ninja Runner', 700 UNION ALL SELECT '2015-09-07', 'Sky Force', 1000 UNION ALL SELECT '2015-09-08', 'ZigZag', 10000 SELECT TMP.REPORTDATE, TMP.GAMENAME, ISNULL(T.TOTAL, 0) FROM ( SELECT distinct GAMENAME, A.REPORTDATE FROM @TBL CROSS JOIN ( SELECT '2015-09-03' as 'REPORTDATE' UNION ALL SELECT '2015-09-04' UNION ALL SELECT '2015-09-05' UNION ALL SELECT '2015-09-06' UNION ALL SELECT '2015-09-07' UNION ALL SELECT '2015-09-08' ) A ) TMP LEFT OUTER JOIN @TBL T ON TMP.GAMENAME = T.GAMENAME AND TMP.REPORTDATE = T.REPORTDATE order by 1, 2
Select column_name, column_name, column_name from #report
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