如何从大字符串中提取值？ [英] How to extract values from large string?

问题描述

大家好，



我遇到的情况是我必须提取大字符串中出现的所有值。例如：

Hi everyone,

I have come against a scenario where i have to extract all values where it occurs in a large string. For example:

string longString = "val{1}:val{5}/val{10}";

所以我想提取出现在 val {} 的所有值;



结果应该是：

1

5

10



我去过尝试使用indexOf做这个但运气不好。有什么方法可以做到这一点？



我很感激任何建议！ ：）

So i want to extract all values that occur where val{ };

The result should be:
1
5
10

I have been trying to do this using indexOf but with not much luck. What would be easy way to accomplish this?

I'd appreciate any advice! :)

推荐答案

string longString = "val{1}:val{5}/val{10}";
var Digits = Regex.Matches(longString, "[0-9]+");
List<string> LstDigit= new List<string>();
foreach (Match Digit in Digits)
{    
    LstDigit.Add(Digit.ToString());
}

问候..

Regards..

你好，

试试这个方式

Hello ,
Try this way

string longString = "val{124}:val{50}/val{100}";
		//first split the string into two parts from semicolon
		string[] sp=longString.Split(':');
		
		//then get the first part by using substring , here 1234
		
		Console.WriteLine("First Part is " + sp[0].ToString().Substring(4,sp[0].ToString().Length-5));
		
		
		//again split the first array into two parts 
		string second=sp[1].ToString() ;
		string[] secondarrary=second.Split('/'); 
		
		//Now get second and third part using substring 
		Console.WriteLine("Second Part is " + secondarrary[0].ToString().Substring(4,secondarrary[0].Length-5));
		Console.WriteLine("Third  Part is " + secondarrary[1].ToString().Substring(4,secondarrary[1].Length-5));

和OP是

and OP is

First Part is 124
Second Part is 50
Third  Part is 100

使用System.Text.RegularExpressions添加引用

add the reference

using System.Text.RegularExpressions;

然后添加以下代码

Then add the following code

string[] numbers = Regex.Split("val{1}:val{5}/val{10}", @"\D+").Where(x => !string.IsNullOrEmpty(x)).ToArray();

最后你会得到一个包含所有数字的字符串数组

And finally you will get a string array which will contain all the numbers

这篇关于如何从大字符串中提取值？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！