如何从多个文本框中打开保存在文件中的数据 [英] How do I open data saved in a file from multiple textboxes

问题描述

所以我的问题是我想要打开以前保存到多个文本框中的文件的数据，我想要打开该文件时，为了保存在文本框中的数据在我打开后向我显示相同的内容，例如在textbox1中它是书面名称，textbox2姓氏，textbox3出生日期等等。所以如果我按此顺序写我希望我显示，我的问题是当我打开它时显示如下：

textbox1： NameSurnameDateofbirth，与开放后我得到的所有文本框完全相同。



以下是saveFileDialog和OpenFileDialog的代码：



打开文件对话框

So my problem is that I want to open data that are previously saved to a file from multiple textboxes, and I want when I open that file in order the data that has been saved in textboxes to show me same thing after I open, e.g. in textbox1 it is written name, textbox2 surname, textbox3 date of birth etc. so if I write in this order I want me to show, my problem is when I open it shows like this:
textbox1: NameSurnameDateofbirth, the exact same thing to all textboxes I get this after opening.

Here are the codes for saveFileDialog and OpenFileDialog:

Open File Dialog

private void openToolStripMenuItem_Click(object sender, EventArgs e)
       {
           if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
           {
               label1.Text = openFileDialog1.FileName;
              textBox1.Text = File.ReadAllText(label1.Text);
               textBox2.Text = File.ReadAllText(label1.Text);
               textBox3.Text = File.ReadAllText(label1.Text);
               textBox4.Text = File.ReadAllText(label1.Text);
               textBox5.Text = File.ReadAllText(label1.Text);
               textBox6.Text = File.ReadAllText(label1.Text);
               textBox7.Text = File.ReadAllText(label1.Text);
               textBox8.Text = File.ReadAllText(label1.Text);
               textBox9.Text = File.ReadAllText(label1.Text);
           }
       }

并保存文件对话框：

And Save File Dialog:

private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
        {
            if (saveFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
            {
                File.WriteAllText(saveFileDialog1.FileName, "");
                    File.AppendAllText(saveFileDialog1.FileName, textBox1.Text);
                    File.AppendAllText(saveFileDialog1.FileName, textBox2.Text);
                    File.AppendAllText(saveFileDialog1.FileName, textBox3.Text);
                    File.AppendAllText(saveFileDialog1.FileName, textBox4.Text);
                    File.AppendAllText(saveFileDialog1.FileName, textBox5.Text);
                    File.AppendAllText(saveFileDialog1.FileName, textBox6.Text);
                    File.AppendAllText(saveFileDialog1.FileName, textBox7.Text);
                    File.AppendAllText(saveFileDialog1.FileName, textBox8.Text);
                    File.AppendAllText(saveFileDialog1.FileName, textBox9.Text);
            }
        }

推荐答案

如果我理解你的问题，请使用ReadAllLines [ ^ ]而不是ReadAllText。这将为您提供一系列字符串，您可以使用这些字符串将正确的行分配给相应的文本框。



类似于

If I understand your question correctly, use ReadAllLines[^] instead of ReadAllText. This would give you an array of strings which you can use to assign correct 'lines' to corresponding text boxes.

So something like

private void openToolStripMenuItem_Click(object sender, EventArgs e)
       {
          string fileName;
          string[] lines;

           if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
           {
               fileName = openFileDialog1.FileName;
               label1.Text = fileName;
               lines = File.ReadAllLines(fileName);
               textBox1.Text = lines[0];
               textBox2.Text = lines[1];
               textBox3.Text = lines[2];
               textBox4.Text = lines[3];
               textBox5.Text = lines[4];
               textBox6.Text = lines[5];
               textBox7.Text = lines[6];
               textBox8.Text = lines[7];
               textBox9.Text = lines[8];
           }
       }

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