从XML获取数据并将其放入链接中？ [英] Get data from XML and put it in a link?

问题描述

[重新发布 XML检查重复项，然后保存，如果重复发现告诉我这件事 - SA]





再次问好，



我想要实现的目的是阅读我的部分XML并将该节点放入网页链接。



IE



www.Helloworld.com/[APIKEY]/[VCODE].jpg



你可以看到我有一个ID，所以当我想做倍数。



我的XML看起来像这样。

[Re-posted XML checking for duplicates before saving, if duplicate found tell me about it — SA]


Hello again,

what im trying to achive is to read part of my XML and put that node into a weblink.

I.E

www.Helloworld.com/[APIKEY]/[VCODE].jpg

as you can see i've got an ID so when i want to do multiples.

My XML looks like this.

  </L><?xml version="1.0" encoding="utf-8"?>
<L xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ID>1c890a19-deae-406b-9e3f-5aeb779d06d4</ID>
  <APIKEY>123</APIKEY>
  <VCODE>123</VCODE>
</L><?xml version="1.0" encoding="utf-8"?>
<L xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ID>d179e9de-ec45-4986-9081-48ebb7466e46</ID>
  <APIKEY>1234</APIKEY>
  <VCODE>1234</VCODE>
</L><?xml version="1.0" encoding="utf-8"?>
<L xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ID>a169216d-efba-4bc2-86a8-1ba8fee3e585</ID>
  <APIKEY>12345</APIKEY>
  <VCODE>12345</VCODE>
</L> 

以下是我制作XML的方法。

Here is how i made my XML.

public class L
   {
       static void main(string[] args)
       {
           XmlDocument xmldoc = new XmlDocument();
           xmldoc.Load("data.XML");
           XmlNodeList userNodes = xmldoc.SelectNodes("data.XML");
           foreach (XmlNode userNode in userNodes) ;

       }

       private string id;
       private string APIkey;
       private string VCode;

       public string ID
       {
           get { return id; }
           set { id = Guid.NewGuid().ToString(); }
       }

       public string APIKEY
       {
           get { return APIkey; }
           set { APIkey = value; }
       }

       public string VCODE
       {
           get { return VCode; }
           set { VCode = value; }

       }

       public static void SaveData(object obj, string Filename)
       {

           XmlSerializer sr = new XmlSerializer(obj.GetType());
           TextWriter writer = new StreamWriter(Filename, true);
           sr.Serialize(writer, obj);
           writer.Close();

       }

我试图在这里使用链接+信息导入图片我的XML。

Im trying to import a picture here using the link + the info in my XML.

private void pictureBox1_Click(object sender, EventArgs e)
      {
          pictureBox1.ImageLocation = "www.Helloworld.com /[line in XML] /[the other line].jpg";

      }

提前致谢：）

Thanks in advance :)

推荐答案

你不能这样做，因为你的数据文件是 而不是XML文件 。尝试打开任何浏览器;它会告诉你原因。 XML应该有一个根元素。有一个正确的XML文件，首先，格式良好，它会工作。





或者，创建自己的专有标准，称之为SuperXML（特别是如果它将成为XML的超集）并创建自己的生成器，解析器，或者可能是序列化。这是很有可能。只避免名称XML，甚至更好的文件命名方案* .XML。

[结束编辑]



但等一下...人们已经向您解释了这个问题：在保存之前检查重复项的XML，如果发现重复告诉我 [ ^ ]。



为什么你会忽略这些评论？请记住，重新发布被视为滥用。这里的主要部分是：如果您不能使用已经获得的建议，谁愿意在重新发布的问题上浪费时间？现在有一点希望你会使用。

-SA

You cannot do it, because you data file is not an XML file. Try to open it any browser; it will tell you why. XML should have one root element. Have a correct XML file, first of all, well-formed, and it will work.


Alternatively, create your own proprietary standard, call it, say, "SuperXML" (especially if it is going to be a superset of XML) and create your own generator, parser, and perhaps serialization. It is quite possible. Only avoid the name "XML" and better even the file naming schema *.XML.
[END EDIT]

But wait a minute… People already explained you this problem: XML checking for duplicates before saving, if duplicate found tell me about it[^].

Why would you ignore those comments? And remember, re-posting is considered as abuse. Main part here is: if you cannot use advice which you already got, who would like to waste time on your re-posted questions? There is a little hope now that you will use the.

—SA

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