如果两个数字相差1，如何输出字符串 [英] How do I output a string out if two numbers differs by 1

问题描述

当input1和input2之间的差值小于0.1时，如何输出文本。

可以包括负双倍和正双倍吗？

  #include   < ;   iostream  >  
   using   namespace  std; 
 
  int  main（）
 {
  double  input1 =  0 。 00 ; 
  double  input2 =  0 。 00 ; 
  bool  input =  true ; 
 
 cout<<  请输入第一个数字<<的std :: ENDL; 
 cin>> input1; 
 cout<<  请输入第二个数字<< std :: endl ; 
 cin>> input2; 
  double  input_diff = input1-input2; 
 cout<<  输入差异为<< input_diff<< endl ; 

我试图把它放在上面的代码之后，但它会产生错误。

  if （input_diff>  -   2 。< span class =code-digit> 0 &<  2 。 0 ） { //  这里有什么问题？ 
x = 真; 
 cout<<  两者之间的值几乎相等<< ENDL; 
 
} 
} 

解决方案

你的&<是胡言乱语。试想一下：是否有这样的运营商？

条件可能是（input_diff> -2.0）& （input_diff< 2.0）;如果在圆括号上需要任何表达。



你关于0.1和负面的问题只是一团糟;你写0.1然后2.0，依此类推。请自己解决。小学数学包含在计算的先决条件中，这是你需要知道的最小部分。

-SA

How can I output the text when the difference between input1 and input2 is less than 0.1.
Can it includes both negative double and positive double?

#include <iostream>
using namespace std;

int main()
{
double input1=0.00;
    double input2=0.00;
    bool input=true;

    cout<<"Please enter first number"<<std::endl;
    cin>>input1;
    cout<<"Please enter second number"<<std::endl;
    cin>>input2;
    double input_diff=input1-input2;
    cout<<"input difference is "<<input_diff<<endl;

I tried to put this after the code above, but it produces error.

    if (input_diff > -2.0 & < 2.0){      // What is wrong here?
        x=true;
        cout<<"The value between the two is almost equal"<<endl;

    }
}

解决方案

Your "& <" is gibberish. Just think about it: is there such operator?
The condition could be (input_diff > -2.0) & (input_diff < 2.0); and if requires any expression on round brackets.

Your questions about 0.1 and negative is just a mess; you write 0.1 and then 2.0, and so on. Please sort it out yourself. Mathematics for elementary school is included in prerequisites for computing, a really smallest part of what you need to know.

—SA

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