如何从Arduino nano打印两个不同的vaule到c＃程序 [英] How to print two different vaules from Arduino nano to a c# program

问题描述

我最近为了个人目的买了一个Arduino nano。我还开发了一个草图，可以从纳米读取电压，可以打开/关闭引脚D2，并获得引脚d2的当前状态（开或关）（使用变量i的状态）。我的目的是用相同的C＃程序手动测量电压和开/关引脚d2，以便同时了解引脚的状态。我现在开发了一个程序，我将结果从nano打印到标签上，看看引脚是打开还是关闭（那时草图只是开/关引脚d2的一点点）。



现在我在草图上添加了代码来测量电压。但我不知道如何从这个草图中获得2个不同的用于在c＃中完成2个不同的工作。请帮忙。



=======

sketch

===== ==

I recently bought a Arduino nano for my personal purpose. I also developed a sketch that can read voltage from nano and can on/off pin D2 and to get the current status of the pin d2(on or off)( status using the variable i). My purpose is to measure voltage and on/off pin d2 manually with same C# programand to know the status of pin at same time . i developed a program now i am printing the result from nano to a label to see whether the pin is on or off(at that time sketch was little bit only for on/off pin d2).

now i added codes to the sketch to measure the voltage. but i dont know how to get 2 different out from this sketch for doing 2 different work in c#. any one help please.

=======
sketch
=======

int LED= 2;
char data;
char x='f';
int analogpin=3;
void setup() {
  {
    Serial.begin(9600);
    pinMode(LED,OUTPUT);
    pinMode(analogpin,INPUT);
    Serial.begin(9600);
  }

}

void loop() {
  ////////////////
   int value = analogRead(analogpin);
  Serial.println(value);
  ////////////////////////////////
 data= Serial.read();

  if  (data=='o')
   {
    digitalWrite(LED,HIGH);
    x = data;
    }
    else if (data=='f')
    {
      digitalWrite(LED,LOW);
      x = data;
      }
///////////////////////////////////
if (data !='o'||data !='f')
  {
    data=x;
    }
//////////////////////////////////////
char i;
  if (data == 'o')
    {
     i='O';
    }
    else if (data == 'f')
      {
        i= 'F';
      }
      else if (data == ' ')
      {
        i='F';
      }
      Serial.println(i);
      
     delay(1000);
}

============================

c＃开/关引脚D2的代码

============================

============================
c# code for on/off pin D2
============================

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.IO.Ports;
namespace WindowsFormsApplication3
{
    public partial class Form1 : Form
    {
        public SerialPort myport;
        public Form1()
        {
            InitializeComponent();
            init();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            myport.WriteLine("o");
            on.Enabled = false;
            off.Enabled = true;
        }

        private void Form1_Load(object sender, EventArgs e)
        {
            try
            {
                myport = new SerialPort();
                myport.BaudRate = 9600;
                myport.PortName = "COM5";
                myport.Open();

            }
            catch (Exception)
            {
                MessageBox.Show("Error");
            }

            
        }
        private void init()
        {
            
            on.Enabled = true;
            off.Enabled = false;
        }

        private void off_Click(object sender, EventArgs e)
        {
            myport.WriteLine("f");
            on.Enabled = true;
            off.Enabled = false;
        }

        private void timer1_Tick(object sender, EventArgs e)
        {
            label1.Text =myport.ReadLine();
            
            }
        }
    }

推荐答案

简单地添加<出了什么问题？ code>'v'命令你的 {'o'，'f'} 命令设置只是为了从arduino获得电压？





[更新]

类似

What's wrong in simply adding a 'v' command to your {'o', 'f'} command set just to get the voltage from the arduino?


[update]
Something like

if  (data=='o')
 {
   digitalWrite(LED,HIGH);
 }
 else if (data=='f')
 {
   digitalWrite(LED,LOW);
 }
 else if ( data=='v')
 {
   // write voltage measured value on the serial port
 }
 else
 {// handle error (unrecognized command)
 }

当然你还要适当地适应 C＃方。

[/ update]

Of course you have also to adapt properly the C# side.
[/update]

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