嗨，我如何修复此错误：属性或索引器'状态'无法分配 - 它是只读的 [英] Hi, How Do I Fix This Error : Property Or Indexer 'Status' Cannot Be Assigned To -- It Is Read Only

问题描述

这是我的代码

this is my code

var filteredQuery = ProjectProvider.GetProjects()
                                                     .Select(a => new ProjectGrid()
                                               {
                                                Id = a.Id,
                                                ClientId = a.ClientId,
                                                ProjectName = a.ProjectName,
                   this is where my error is -> StatusType = a.Status,
                                                CostCode = a.CostCode,
                                                Description = a.Description
                                                     });

推荐答案

在ProjectGrid中确保StatusType有一个get和（非私有）设置。

In ProjectGrid make sure StatusType has a get and (non-private) set.

public YourType StatusType {get; set;}

在类定义中它只有一个得到。或者可能是类型在别处计算并且不是标准属性。如果是这种情况，你需要设置类，使其StatusType返回你想要的状态。

In its class definition it'll only have a "get". Or it could be that the type is computed elsewhere and isn't a standard property. If that's the case you'll need to set the class up such that its StatusType returns the status you want.

public YourType StatusType
{
    get
    {
        // look at how the status type is calculated and work out
        // from that how to set it
        return SomeFunctionThatCalculatesType();
    }   
}

鉴于您发布的信息很少，任何后续问题都不太可能回答，我们不知道你的系统，它的规则，我们无法访问你的代码和数据库。

Given the minimal information you have posted, it is unlikely any follow-up questions can be answered, we don't know your system, its rules, we can't access your code and databases.

使用public< datatype>声明属性。 status {get; set;}

或类似

public< datatype>状态;

这可能会解决您的问题

Declare the property with public <datatype> status{get;set;}
or like
public <datatype> status;
this will probably solve your problem

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