如何根据文件名获取文件路径。 [英] How to get the file path based on file name.

问题描述

如何根据C ++或MFC中的文件名获取完整文件路径



Ex。我有基于此文件名的文件名txtone.txt我需要获取完整路径

，如果它在D：\ folder1 \ folder2 \ txtone.txt

解决方案

您可以做的最好的事情是递归搜索这样的文件。然后你将处理（可能）多个结果。例如，请参阅此Stack Overflow问题：使用C ++ MFC进行递归文件搜索？ [ ^ ]。

How to get the full file path based on the file name in the C++ or MFC

Ex. i have file name txtone.txt based on this file name i need to get the fullpath
like if it is in D:\folder1\folder2\txtone.txt

解决方案

The best you can do is recursively search for such a file. Then you are going to deal with (possibly) multiple results. See for instance this Stack Overflow question: "Recursive file search using C++ MFC?"[^].

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