C＃平均每组20个数据 [英] C# To average of each group of 20 data
本文介绍了C＃平均每组20个数据的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我想平均每组20个Barycentre_x Barycentre_y和Barycentre_z的数据。这些变量有许多cpt线（大约600行）。
我尝试这样做，但它没有' t run。
Barycentre_x = new double [cpt - 1 ];
Barycentre_y = new double [cpt - 1 ];
Barycentre_z = new double [cpt - 1 ];
for （ int i = 0 ; i < cpt-1; i ++）{
for （ int l = 55 ; l < 63 ; l ++）{
Barycentre_x [i] + = nv_data [l] .positions [i] .x;
Barycentre_y [i] + = nv_data [l] .positions [i] .y;
Barycentre_z [i] + = nv_data [l] .positions [i] .z;
}
Barycentre_x [i] / = 8 ;
Barycentre_y [i] / = 8 ;
Barycentre_z [i] / = 8 ;
}
// 这里我开始平均值
Moy_bar_x = new double [Barycentre_x.Length / 20 ];
Moy_bar_y = new double [Barycentre_y.Length / 20 ];
Moy_bar_z = new double [Barycentre_z.Length / 20 ];
while （index_moy + 20 < Barycentre_z.Length）{
Moy_bar_x [index_moy％ 20 ] + = Barycentre_x [index_moy];
Moy_bar_y [index_moy％ 20 ] + = Barycentre_y [index_moy];
Moy_bar_z [index_moy％ 20 ] + = Barycentre_z [index_moy];
index_moy ++;
如果（index_moy％ 20 == 0 ）{
indice_2 ++;
Moy_bar_x [indice_2] / = 20 ;
Moy_bar_y [indice_2] / = 20 ;
Moy_bar_z [indice_2] / = 20 ;
}
}
代码的开头：
int index_moy = 0;
int indice_2 = -1;
解决方案
试试这个;
静态 void Main（字符串 [] args）
{
const int cpt = 153 ;
const int taille = 20 ;
const double X = 21 。 5 ;
const double Y = -1。 98 ;
const double Z = 1100 。 0 ;
double [] Barycentre_x = new double [cpt];
double [] Barycentre_y = new double [cpt];
double [] Barycentre_z = new double [cpt];
随机rand = 新 Random（）;
for （ int n = 0 ; n < cpt; ++ n）
{
Barycentre_x [n] = X +（rand.NextDouble（） - 。 5 ）* Math.Abs（X）/ 100. 0 ;
Barycentre_y [n] = Y +（rand.NextDouble（） - 。 5 ）* Math.Abs（Y）/ 100. 0 ;
Barycentre_z [n] = Z +（rand.NextDouble（） - 。 5 ）* Math.Abs（Z）/ 100. 0 ;
}
const int groupes = cpt / taille;
double [] Moy_bar_x = new 双 [groupes];
double [] Moy_bar_y = new double < /跨度> [groupes];
double [] Moy_bar_z = new double < /跨度> [groupes];
int index = 0 ;
for （ int g = 0 ; g< groupes; ++ g）
{
Moy_bar_x [g] = Moy_bar_y [g] = Moy_bar_z [g] = 0 。 0 ;
for （ int n = 0 ; n< taille; ++ n，++ index）
{
Moy_bar_x [g] + = Barycentre_x [index];
Moy_bar_y [g] + = Barycentre_y [index];
Moy_bar_z [g] + = Barycentre_z [index];
}
Moy_bar_x [g] / = taille;
Moy_bar_y [g] / = taille;
Moy_bar_z [g] / = taille;
}
for （ int g = 0 ; g < groupes; ++ g）
{
Console.WriteLine（ Moy_bar =（{0}，{1}，{2}），Moy_bar_x [g]，Moy_bar_y [g]，Moy_bar_z [g]）;
}
}
如果你想做一个移动平均线，那么有两种方法可以做到：
1）将最后20个项目保留在数组或类似项目中，并每次更换最旧的项目，然后重新排列数组。
2）保持运行总计，当你有二十个项目时，从总数中减去当前位置二十的值，然后加上当前值。
如果你想把它们加起来二十组，然后只使用两个循环：
外循环迭代组（即二十几岁的移动）
内循环在一个组内迭代。
您只需要两个索引（输出组，输入组）和两个计数。
int a = -1;
int f = 1 ;
Moy_bar_x = new double [Barycentre_x.Length / 20 ];
Moy_bar_y = new double [Barycentre_y.Length / 20 ];
Moy_bar_z = new double [Barycentre_z.Length / 20 ];
while （a < （Barycentre_z.Length / 20 ） - 1）{
a ++;
while （（f％ 20 ）！= 0 ）{
Moy_bar_x [a] + = Barycentre_x [f];
Moy_bar_y [a] + = Barycentre_y [f];
Moy_bar_z [a] + = Barycentre_z [f];
f ++;
}
f + = 1 ;
}
for （ int b = 0 ; b < Moy_bar_z.Length; b ++）{
Moy_bar_x [ b] / = 20 ;
Moy_bar_y [b] / = 20 ;
Moy_bar_z [b] / = 20 ;
}
Hello !
I want to average of each group of 20 data of Barycentre_x Barycentre_y and Barycentre_z. These variables have a number of "cpt" lines (around 600 lines).
I try to do this, but it doesn't run.
Barycentre_x = new double[cpt - 1];
Barycentre_y = new double[cpt - 1];
Barycentre_z = new double[cpt - 1];
for (int i = 0; i < cpt-1; i++) {
for (int l = 55; l < 63; l++) {
Barycentre_x [i] += nv_data [l].positions [i].x;
Barycentre_y [i] += nv_data [l].positions [i].y;
Barycentre_z [i] += nv_data [l].positions [i].z;
}
Barycentre_x [i] /= 8;
Barycentre_y [i] /= 8;
Barycentre_z [i] /= 8;
}
// Here I begin the average
Moy_bar_x = new double[Barycentre_x.Length / 20];
Moy_bar_y = new double[Barycentre_y.Length / 20];
Moy_bar_z = new double[Barycentre_z.Length / 20];
while (index_moy + 20 < Barycentre_z.Length) {
Moy_bar_x [index_moy % 20] += Barycentre_x [index_moy];
Moy_bar_y [index_moy % 20] += Barycentre_y [index_moy];
Moy_bar_z [index_moy % 20] += Barycentre_z [index_moy];
index_moy ++;
if (index_moy % 20 == 0) {
indice_2++;
Moy_bar_x [indice_2] /= 20;
Moy_bar_y [indice_2] /= 20;
Moy_bar_z [indice_2] /= 20;
}
}
At the beginning of the code :
int index_moy = 0;
int indice_2 = -1;
解决方案
Try this;
static void Main(string[] args) { const int cpt = 153; const int taille = 20; const double X = 21.5; const double Y = -1.98; const double Z = 1100.0; double [] Barycentre_x = new double [cpt]; double [] Barycentre_y = new double [cpt]; double [] Barycentre_z = new double [cpt]; Random rand = new Random(); for (int n=0; n < cpt; ++n) { Barycentre_x[n] = X + (rand.NextDouble()-.5) * Math.Abs(X)/100.0; Barycentre_y[n] = Y + (rand.NextDouble()-.5) * Math.Abs(Y)/100.0; Barycentre_z[n] = Z + (rand.NextDouble()-.5) * Math.Abs(Z)/100.0; } const int groupes = cpt / taille; double [] Moy_bar_x = new double[groupes]; double [] Moy_bar_y = new double[groupes]; double [] Moy_bar_z = new double[groupes]; int index = 0; for (int g = 0; g< groupes; ++g) { Moy_bar_x[g] = Moy_bar_y[g] = Moy_bar_z[g]= 0.0; for (int n=0; n<taille; ++n, ++index) { Moy_bar_x [g] += Barycentre_x [index]; Moy_bar_y [g] += Barycentre_y [index]; Moy_bar_z [g] += Barycentre_z [index]; } Moy_bar_x[g] /= taille; Moy_bar_y[g] /= taille; Moy_bar_z[g] /= taille; } for (int g = 0; g < groupes; ++g) { Console.WriteLine("Moy_bar = ({0},{1},{2})", Moy_bar_x[g], Moy_bar_y[g], Moy_bar_z[g]); } }
If you want to do a moving average, then there are two ways you can do it:
1) Keep the last twenty items in an array or similar, and replace the oldest with the latest each time, then re-sum the array.
2) Keep a running total, and when you have twenty items, subtract the value at current-position-twenty from the total, and add the current value.
If you are trying to sum them in groups of twenty, then just use two loops:
Outer loop iterates groups (i.e. moves on in twenties)
Inner loop iterates within a group.
All you need is two indexes (group for output, input) and two counts.
int a = -1; int f = 1; Moy_bar_x = new double[Barycentre_x.Length / 20]; Moy_bar_y = new double[Barycentre_y.Length / 20]; Moy_bar_z = new double[Barycentre_z.Length / 20]; while (a < (Barycentre_z.Length / 20)-1) { a++; while ((f % 20) !=0) { Moy_bar_x [a] += Barycentre_x[f]; Moy_bar_y [a] += Barycentre_y[f]; Moy_bar_z [a] += Barycentre_z[f]; f++; } f += 1; } for (int b = 0; b < Moy_bar_z.Length; b++) { Moy_bar_x[b] /= 20; Moy_bar_y[b] /= 20; Moy_bar_z[b] /= 20; }
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