如何将char [] []转换为char [，] [英] How to convert char[][] to char[,]

问题描述

我想将char [] []转换为char [，]或

List< char []> to char [，]。



请帮我解决这个问题

解决方案

你不一定这样做。

一个 char [] [] 或 List< char []> 是锯齿状数组 - 并非集合中的所有元素都被定义为相同的长度。

例如：

< pre lang =c＃> char [] [] arr = new char [] [] {{' 1'，' 2'}，{' 1'，' 2'，' 3'}，{' 1'，' 2'}};

您无法将其转换为 char [，] 数组，因为第一行和第二行的第二个维度大小说明符不同 - 而char不是可空类型，所以你甚至不能为缺失元素分配一个默认值来整理它！ />


可以这样做： http://stackoverflow.com/questions/26291609/converting-jagged-array-to-2d-array-c-sharp [ ^ ]但你很有可能会更好地重新思考你正在做的是首先创建锯齿状数组！




  static   char  [，] To2D（List< char [] >  a）
 {
  int  Max =  0 ; 
  int  aCount = a.Count; 
  for （ int  i =  0 ; i <  aCount; i ++）Max = Max< a [i] .length？a [i] .length：max; >  
  char  [，] Out =  new  < span class =code-keyword> char  [aCount，Max]; 
  for （ int  i =  0 ; i< acount; i ++）>  
  for （ int  j =  0 ; j< a [i] .length; j ++）> ;  
 {
 Out [i，j] = a [i] [j]; 
} 
  return  Out; 
} 




I want to convert char[][] to char[,] or
List<char[]> to char[,].

please help me for solve this

解决方案

You can't necessarily do that.
An array of char[][] or List<char[]>is a jagged array - not all the elements in the collection are defined as being the same length.
For example:

char[][] arr = new char[][] {{'1','2'}, {'1', '2', '3'}, {'1', '2'}};

You can't convert that to a char[,] array because the second dimension size specifier is different for the first and second rows - and char is not a nullable type, so you can't even assign a "default value" to "missing" elements to tidy it up!

It can be done: http://stackoverflow.com/questions/26291609/converting-jagged-array-to-2d-array-c-sharp[^] but there is a good chance you would be better off rethinking what you are doing to create the jagged array in the first place!




static char[,] To2D(List<char[]> a)
        {
            int Max = 0;
            int aCount=a.Count;
            for (int i = 0; i < aCount; i++) Max=Max<a[i].length?a[i].length:max;>
            char[,] Out = new char[aCount, Max];
            for(int i=0;i<acount;i++)>
                for(int j=0;j<a[i].length;j++)>
                {
                    Out[i, j] = a[i][j];
                }
            return Out;
        }




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