JsonConverter（typeof（））无法处理以下json响应。 [英] JsonConverter(typeof()) is not working to handle following json response.

问题描述

我从API调用调用API和Response如下。当我使用 JsonConvert.DeserializeObject< class1>（resp）因为不同调用的参数类型发生变化时，它会抛出异常。我使用 JsonConverter（typeof（））来处理类型转换。但它没有用。当json响应参数的类型发生变化时，如何处理？

I am calling API and Response from the API call is as follows. It throws Exception when I used JsonConvert.DeserializeObject<class1>(resp) as because type of the parameters changes for different call. I have used JsonConverter(typeof()) to handle type conversion. But it is not working. How can i handle when type of the parameters of the json response changes?

public class class1
{  
    public double lat { get; set; }
    public double @long { get; set; }
    public int orra { get; set; }
    public List<string> hotelPolicy { get; set; }
}

public class class1
{   
    public object lat { get; set; }
    public object @long { get; set; }
    public double orra { get; set; }
    public List<object> hotelPolicy { get; set; }
}

推荐答案

我不认为这个问题有一个神奇的银弹。



我建议根据几个预定义模式之一验证传入的JSON数据。如果它针对特定模式进行验证，则可以安全地针对您的DTO类调用JsonConvert.DeserializeObject< T>（）。



JSON模式验证 [ ^ ]



这种方法性能更高（避免了引发运行时异常的开销）<另一个更直接的方法就是创建一个'TryParse'样式函数，它可以吞下任何异常，并多次调用它，直到有效结果为止。返回...

I don't think there is a magic silver bullet for this issue.

I would suggest validating the incoming JSON data against one of several pre-defined schemas. If it validates against a particular schema, you can safely call JsonConvert.DeserializeObject<T>() against your DTO class.

JSON Schema Validation[^]

This approach as more performant (it avoids the overhead of raising runtime exceptions)

The other more straight-forward approach would just be to create a 'TryParse' style function, which swallows any exceptions, and call it multiple times, until a valid result is returned ...

public bool TryParseJson<T>(string json, out T value) where T: class, new()
{
    value = new T();
    bool result = false;
    try{
        value = JsonConvert.DeserializeObject<T>(json);
        result = true;
    }catch(Exception)
    {
    }
    return result;
}

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