如何使用c语言计算日期差异 [英] How to calculate the date difference using c languvage

问题描述

亲爱的先生，



如何计算今天（到）最后一天的日期差异。



i希望这个程序使用C Languvage。



请给我回答。



例如：



今日日期：18.08.2012

最后一天：30.05.2012

___________

答案12.03 .21

dear sir,

How to calculate the date difference in today (to) last day .

i want this program using C Languvage.

please give me answer.

Example:

Today Date:18.08.2012
last day:30.05.2012
___________
Answer 12.03 .21

推荐答案

查看这些链接..这将解决您的问题..

< a href =http://cboard.cprogramming.com/c-programming/97842-getting-difference-between-dates.html> http://cboard.cprogramming.com/c-programming/97842-getting-difference -between-dates.html [ ^ ]

HTTP：//cboard.cprogra mming.com/c-programming/108714-review-required-program-date-difference.html [ ^ ]

http://stackoverflow.com/questions/1444428/time-stamp-in-the-c-programming-language [ ^ ]

See these links..it will solve your problem..
http://cboard.cprogramming.com/c-programming/97842-getting-difference-between-dates.html[^]
http://cboard.cprogramming.com/c-programming/108714-review-required-program-date-difference.html[^]
http://stackoverflow.com/questions/1444428/time-stamp-in-the-c-programming-language[^]

包括< stdio.h>

包括< conio.h>

< br $>


int main（）

{

int fd，fm，fy，sd，sm，sy，ty ，tday，rday，i，r，c1，c2;

printf（条目类似日期< space> Month< space> Year \ n）;

printf （输入你的第一个日期：）;

scanf（％d％d％d，& fd，& fm，& fy）;

的printf（恩特r你的第二个日期：）;

scanf（％d％d％d，& sd，& sm，& sy）;

ty = fy-sy;

tday = ty * 365;

tday--;

fy--;

for（i = sy; i< = fy; i ++）

{

r = i％4;

if（r == 0）

{

tday ++;

}

}

c1 = - fm ;

开关（c1）

{

案例1：tday = tday + 31;休息;

案例2：tday = tday + 59; fy ++; r = fy％4; if（r == 0）{tday ++;} break;

case 3：tday = tday + 90; fy ++; r = fy％4; if（r == 0）{tday ++;} break;

case 4：tday = tday + 120; fy ++; r = fy％4; if（r == 0）{ tday ++;} break;

case 5：tday = tday + 151; fy ++; r = fy％4; if（r == 0）{tday ++;} break;

情况6：tday = tday + 181; fy ++; r = fy％4; if（r == 0）{tday ++;} break;

case 7：tday = tday + 212; fy ++; r = fy％4; if（r == 0）{tday ++;} break;

case 8：tday = tday + 243; fy ++; r = fy％4; if（r = = 0）{tday ++;} break;

case 9：tday = tday + 273; fy ++; r = fy％4; if（r == 0）{tday ++;} break;

案例10：tday = tday + 304; fy ++; r = fy％4; if（r == 0）{tday ++;} break;

case 11：tday = tday + 334; fy ++; r = fy％4; if（r == 0）{tday ++;} break;

}

tday = tday + fd;

c2 = - sm;

开关（c2）

{

案例1：rday = 31;休息;

案例2：rday = 59; r = sy％4; if（r == 0）{rday ++;} break;

case 3：rday = 90; r = fy ％4; if（r == 0）{rday ++;} break;

case 4：rday = 120; r = fy％4; if（r == 0）{rday ++;} break;

案例5：rday = 151; r = fy％4; if（r == 0）{rday ++;} break;

case 6：rday = 181; r = fy％4; if（r == 0）{rday ++;} break;

case 7：rday = 212; r = fy％4; if（r == 0）{rday ++;}休息;

案例8：rday = 243; r = fy％4; if（r == 0）{rday ++;} break;

案例9：rday = 273 ; r = fy％4; if（r == 0）{rday ++;} break;

case 10：rday = 304; r = fy％4; if（r == 0）{rday ++ ;}打破;
案例11：rday = 334 ;; r = fy％4; if（r == 0）{rday ++;} break;

}

rday = rday + sd;

tday = tday-rday; tday ++;

printf（\ nTotal Days：％d Days，tday）;

getch（）;

}

include<stdio.h>

include<conio.h>

int main()
{
int fd,fm,fy,sd,sm,sy,ty,tday,rday,i,r,c1,c2;
printf("Entry Like Date<space>Month<space>Year\n");
printf("Enter Your 1st Date : ");
scanf("%d %d %d",&fd,&fm,&fy);
printf("Enter Your 2nd Date : ");
scanf("%d %d %d",&sd,&sm,&sy);
ty=fy-sy;
tday=ty*365;
tday--;
fy--;
for(i=sy;i<=fy;i++)
{
r=i%4;
if(r==0)
{
tday++;
}
}
c1=--fm;
switch(c1)
{
case 1:tday=tday+31;break;
case 2:tday=tday+59;fy++;r=fy%4;if(r==0){tday++;}break;
case 3:tday=tday+90;fy++;r=fy%4;if(r==0){tday++;}break;
case 4:tday=tday+120;fy++;r=fy%4;if(r==0){tday++;}break;
case 5:tday=tday+151;fy++;r=fy%4;if(r==0){tday++;}break;
case 6:tday=tday+181;fy++;r=fy%4;if(r==0){tday++;}break;
case 7:tday=tday+212;fy++;r=fy%4;if(r==0){tday++;}break;
case 8:tday=tday+243;fy++;r=fy%4;if(r==0){tday++;}break;
case 9:tday=tday+273;fy++;r=fy%4;if(r==0){tday++;}break;
case 10:tday=tday+304;fy++;r=fy%4;if(r==0){tday++;}break;
case 11:tday=tday+334;fy++;r=fy%4;if(r==0){tday++;}break;
}
tday=tday+fd;
c2=--sm;
switch(c2)
{
case 1:rday=31;break;
case 2:rday=59;r=sy%4;if(r==0){rday++;}break;
case 3:rday=90;r=fy%4;if(r==0){rday++;}break;
case 4:rday=120;r=fy%4;if(r==0){rday++;}break;
case 5:rday=151;r=fy%4;if(r==0){rday++;}break;
case 6:rday=181;r=fy%4;if(r==0){rday++;}break;
case 7:rday=212;r=fy%4;if(r==0){rday++;}break;
case 8:rday=243;r=fy%4;if(r==0){rday++;}break;
case 9:rday=273;r=fy%4;if(r==0){rday++;}break;
case 10:rday=304;r=fy%4;if(r==0){rday++;}break;
case 11:rday=334;;r=fy%4;if(r==0){rday++;}break;
}
rday=rday+sd;
tday=tday-rday;tday++;
printf("\nTotal Days : %d Days",tday);
getch();
}

#includestdio.h



int fy，fm，fd; //用于保存第一个日期的整数

int sy，sm，sd; //整数来保持第二个日期



/ *在此我假设第一个日期大于第二个日期* /



int oy，num_of_days，removed_days; //用于保存输出的整数



int i; //'for-loop'的变量

int c1; //第一个'开关'的变量

int c2; //第二个'开关'的变量



int ex; //退出序列



char line [100]; //输入行



int main（）{

printf（请先选择模式\ n）;

printf（输入1进行计算。\ n）;

printf（输入0退出\ n）;



printf（请输入以下oder \ n中的日期）;

printf（****年****月**日** \ n \\ n'）;



而（1）{



//模式或退出程序

printf（请输入你的需要：）;

fgets（line，sizeof（line），stdin）;

sscanf（line，％d，&ex）;



//进行计算的表达式

if（ex = = 1）{



//第一次约会

printf（请输入第一次约会：）;

fgets（line，sizeof（line），stdin）;

sscanf（行，％d％d％d，&fy，&fm，&fd）;



//第二次约会

printf（请输入第二个日期：） ;

fgets（line，sizeof（line），stdin）;

sscanf（行，％d％d％d，&sy，&sm，&sd）; < br $> b $ b

oy = fy - sy; //取差多年

num_of_days = oy * 365; //设置输出天数



num_of_days--; //多花一天时间



if（fy！= sy）

fy--; //在first_year之前的最后一年





//在第一年和第二年之间取得闰年

for（i = sy; i< = fy; i ++）{



if（i％4 == 0）

num_of_days ++ ;



}



if（fy！= sy）

fy ++ ; //将第一年的值设置为上一个值



//检查第一年是否为跳跃，如果是，则添加一天

if （fy％4）

num_of_days ++;



fm--;

c1 = fm;



//计算第一个月的天数

if（fm< 12）{

switch（c1）

{

案例1：num_of_days + = 31; if（fy％4 == 0）{num_of_days--;} break;

case 2：num_of_days + = 59;休息;

案例3：num_of_days + = 90;休息;

案例4：num_of_days + = 120;休息;

案例5：num_of_days + = 151;休息;

案例6：num_of_days + = 181;休息;

案例7：num_of_days + = 212;休息;

案例8：num_of_days + = 243;休息;

案例9：num_of_days + = 273;休息;

案例10：num_of_days + = 304;休息;

案例11：num_of_days + = 334;休息;

}

}



//无效日期抛出异常

else {

printf（错误：输入有效日期\ n）;

继续;

}



num_of_days + = fd; //添加第一个日期的天数



c2 = --sm;



//计算第二个月的日子

if（sm <12）{

开关（c2）

{

案例1：removed_days + = 31; if（sy％4 == 0）{removed_days--;} break;

case 2：removed_days + = 59;休息;

案例3：removed_days + = 90;休息;

案例4：removed_days + = 120;休息;

案例5：removed_days + = 151;休息;

案例6：removed_days + = 181;休息;

案例7：removed_days + = 212;休息;

案例8：removed_days + = 243;休息;

案例9：removed_days + = 273;休息;

案例10：removed_days + = 304;休息;

案例11：removed_days + = 334;休息;



}

}

//抛出无效天数的例外情况

else {

printf（错误：输入有效日期\ n）;

休息;

}

removed_days + = sd;



//检查第二年是否飞跃

if（sy％4 == 0）

removed_days ++;



//计算天数

num_of_days = num_of_days - removed_days;



printf（％d-％d-％d和％d-％d-％d.\之间有％d天，

num_of_days，fy，++ fm，fd，sy，++ sm，sd）;

ex = 0; //更改退出状态

继续;

}



//退出

else if（ex == 0）{



printf（感谢您使用此服务。\ n）;

休息;



}



//表达错误模式

else {



printf（请输入有效的模式。\ n）;

继续;



}



}





返回（0）;

}

#include "stdio.h"

int fy,fm,fd; //integers to hold first date
int sy,sm,sd; //integers to hold second date

/*in this i have assumed that first date is greater than second date*/

int oy,num_of_days,removed_days; //integers to hold the outputs

int i; //variable for 'for-loop'
int c1; //variable for first 'switch'
int c2; //variable for second 'switch'

int ex; //the exit sequence

char line[100]; //the input line

int main(){
printf("Please select a mode first\n");
printf("Enter 1 to do calculations.\n");
printf("Enter 0 to exit\n");

printf("Please Enter the dates in following oder\n");
printf("****Year****month**date**\n\n");

while(1){

//taking the mode or exit the program
printf("Please enter your need : ");
fgets(line,sizeof(line),stdin);
sscanf(line,"%d",&ex);

//the expressions to do the calculations
if(ex == 1){

//taking the first date
printf("Please enter the first date : ");
fgets(line,sizeof(line),stdin);
sscanf(line,"%d %d %d",&fy,&fm,&fd);

//taking the second date
printf("Please enter the second date : ");
fgets(line,sizeof(line),stdin);
sscanf(line,"%d %d %d",&sy,&sm,&sd);

oy = fy - sy; //taking the difference of the years
num_of_days = oy * 365; //setting output days

num_of_days--; //taking the extra day out

if(fy != sy)
fy--; //to take the last year before first_year


//taking the leap years between first and second year
for(i=sy;i<=fy;i++){

if(i%4 == 0)
num_of_days++;

}

if(fy != sy)
fy++; //setting first year value to previous value

//checking whether first year is leap, if it is then add one day
if(fy%4)
num_of_days++;

fm--;
c1 = fm;

//calculating the days of the first month
if(fm < 12){
switch(c1)
{
case 1 : num_of_days += 31; if(fy%4 == 0){num_of_days--;} break;
case 2 : num_of_days += 59; break;
case 3 : num_of_days += 90; break;
case 4 : num_of_days += 120; break;
case 5 : num_of_days += 151; break;
case 6 : num_of_days += 181; break;
case 7 : num_of_days += 212; break;
case 8 : num_of_days += 243; break;
case 9 : num_of_days += 273; break;
case 10 : num_of_days += 304; break;
case 11 : num_of_days += 334; break;
}
}

//throwing exception for invalid dates
else{
printf("Error : Enter valid date\n");
continue;
}

num_of_days += fd; //adding the days of the first date

c2 = --sm;

//calculating the days of the second month
if(sm < 12){
switch(c2)
{
case 1 : removed_days += 31; if(sy%4 == 0){removed_days--;} break;
case 2 : removed_days += 59; break;
case 3 : removed_days += 90; break;
case 4 : removed_days += 120; break;
case 5 : removed_days += 151; break;
case 6 : removed_days += 181; break;
case 7 : removed_days += 212; break;
case 8 : removed_days += 243; break;
case 9 : removed_days += 273; break;
case 10 : removed_days += 304; break;
case 11 : removed_days += 334; break;

}
}
//throwing exceptions for invalid days
else{
printf("Error : Enter valid date\n");
break;
}
removed_days += sd;

//checking whether second year is leap
if(sy%4 == 0)
removed_days++;

//calculating the number of days
num_of_days = num_of_days - removed_days;

printf("There are %d days between %d-%d-%d and %d-%d-%d.\n",
num_of_days,fy,++fm,fd,sy,++sm,sd);
ex = 0; //to change the exiting status
continue;
}

//the exit
else if(ex == 0){

printf("Thank you for using this service.\n");
break;

}

//the expression to eveluate wrong modes
else{

printf("Please enter a valid mode.\n");
continue;

}

}


return(0);
}

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