语法差异 [英] Difference in syntaxes

问题描述

大家好，



有什么区别：

 char * f（）{} 

和

 char * f（）{} 
 

当我从上面调用上述函数的地方获取值时，语法是什么？

 char * buffer = f（）; 

或

 char * buffer = f（）; 

我google了它但是dint找到了一个令人满意的答案。以上是什么区别语法。



谢谢和问候，

Rahul

解决方案

简而言之因为C是一种自由格式的语言，无论你选择哪种风格都可以，而解析器可以区分每个令牌。

请考虑你的情况甚至：

< pre lang =c ++> char * f（）{}

它完全等同于其他2 。

这个pe C的特殊性导致了一种非常特殊的比赛，称为 C混淆比赛 [ ^ ]。这个网站将为您提供更多答案，所有其他链接在一起...; - ）

请参阅 http： //www.cdecl.org/ [ ^ ]并与之合作你的声明（没有功能体）。



另见在C中，声明指针的正确语法是什么？ [ ^ ]。



顺便说一句：我想知道你是懒惰还是什么 - 这是我在谷歌输入你的问题时的首次点击之一...



干杯

Andi

Hi all,

What is the difference between:

char* f(){}

and

char *f(){}

When i will get the value from where i called the above functions what would the syntax be?

char *buffer=f();

OR

char* buffer=f();

I googled it out but dint find a satisfying answer.And what is the difference between the above syntaxes.

Thanks and Regards,
Rahul

解决方案

In short because C is a free format language, whatever style you choose its ok while the parser can make a distinction of each token.
Please consider that in your case even:

char*f(){}

It's perfectly equivalent top the other 2.
This peculiarity of C lead to a very special type of contest called C obfuscation contest[^]. This site will give you much more answers that all other links together... ;-)

See http://www.cdecl.org/[^] and play with your declarations (without the function body).

See also In C, what is the correct syntax for declaring pointers?[^].

BTW: I wonder if you were lazy or what - this is one of the first hits when I enter your question in Google...

Cheers
Andi

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