这有什么不对 [英] what is wrong in this
本文介绍了这有什么不对的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
INSERT INTO [new].[dbo].[page2]
([Name]
,[City]
,[State]
,[Phone]
,[Salary]
,[Age]
,[Gender])
VALUES
(<name,>
,<city,>
,<state,>
,<phone,>
,<salary,>
,<age,>
,<gender,>)
GO
CREATE PROCEDURE dbo.InsertStudentsData
@Name varchar(35),
@City char(15),
@State char(15),
@Phone bigint(10),
@Salary int(15),
@Age Int(2)
@Gender char(20)
@IdentitY int OUTPUT
AS
BEGIN
INSERT Students (Name,City,[State],Phone,Salary,Age,Gender)
VALUES
(@Name,@City,@State,@Phone,@Salary,@Age,@Gender)
END
SELECT @Identity = SCOPE_IDENTITY();
RETURN @Identity
推荐答案
代码在变量@Age和@Gender之后缺少逗号(,)。
代码的另一个问题是,你不能指定列宽到数据类型int和bigint代码应该是
The code is missing comma(,) after the variables @Age and @Gender.
Another problem with the code is, you cannot specify column width to data types int and bigint The code should be
CREATE PROCEDURE dbo.InsertStudentsData
@Name varchar(35),
@City char(15),
@State char(15),
@Phone bigint,
@Salary int,
@Age Int,
@Gender char(20),
@IdentitY int OUTPUT
AS
BEGIN
INSERT Students (Name,City,[State],Phone,Salary,Age,Gender)
VALUES
(@Name,@City,@State,@Phone,@Salary,@Age,@Gender)
END
SELECT @Identity = SCOPE_IDENTITY();
RETURN @Identity
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